PHP - regex with two conditions

Question

I'm looking for a regex expression to use with php :

I have 4 strings like this in array :

$strA = 'John P. Beck';   // name and surname
$strB = '12012 BlaBla Xx';  // street
$strC = 'Houston TX 12345-6789';  // city + zip code
$strD = '(123) 456-7890';  // telephone number

By now i'm using a regex in a for loop but it always returns me both the first and the second string, and sometimes the first and the third string....

for($i = 0; $i < count($array); $i++)
{
    if(preg_match("/[A-Z]/", $array[$i]))
    {
      echo $array[$i] . '<br>';
    }
    else echo 'no match<br>';
}

I need a regex with this conditions : - at least 1 Uppercase in string AND absolutely NO digits... to return only $strA.....

Thank you very much

EDIT

sorry maybe I explained myself bad and without adding details... This is the structure of the array (example):

[0] => <p>
[1] =>                41
[2] => <br />
[3] =>                John P. Beck
[4] => <br />
[5] =>                12012 BlaBla Xx
[6] => <br />
[7] =>                Houston TX 12345-6789
[8] => <br />
[9] =>                (123) 456-7890
[10] => <br />
[11] =>                42
[12] => <br />
[13] =>                Linda F. Green
[14] => <br />
[15] =>                1888 BlaBla Xx
[16] => <br />
[17] =>                Saint Louis, MO 12345-6789
[18] => <br />
[19] =>                (123) 456-7890
[20] => <br />
...
...
...

I need to store only the 4th string and the 14th string.. and so on ...

@nickb : with $array[0] it returns always a p tag.. i'm in a for loop...... :)

What is "joHn p. beck" ? (only the H is in upercase). Should pass or not ? — AKS
– AKS, Commented Jun 1, 2012 at 23:22
It would help to know some sample inputs and desired outputs. Your edit has <br> which makes me think it is output, but what was the input? — walrii
– walrii, Commented Jun 2, 2012 at 0:27
I am not sure why you need any sort of regex at all if your array is formed like that. Why not taking every item numbered N*10+3 or every item at +2 after a string that represents a valid number? — Eugene Ryabtsev
– Eugene Ryabtsev, Commented Jun 2, 2012 at 11:58
you mean using a division and the mod operator (%) .... ? Yes I think it would be more mathematically correct but i needed a fast solution... I solved it with a regex by samsamX — lollo
– lollo, Commented Jun 2, 2012 at 12:24

zessx · Accepted Answer · 2012-06-05 13:30:07Z

1

0 or more chars (except digits), followed by one or more uppercase letter, followed by 0 or more chars (except digits) :

/[^0-9]*[A-Z]+[^0-9]*/

If you want your data beginning by the uppercase(s) letter(s) :

/^[A-Z]+[^0-9]*/

edited Jun 5, 2012 at 13:30

answered Jun 1, 2012 at 23:27

zessx

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9 Comments

zessx Over a year ago

Show us 2 example isn't enought, you should specify exactly what you want. Are you searching for every 3 parts names ? Like xxxxx X. xxxx or Xxxxx X. xxx or even Xxxx X. Xx ?

lollo Over a year ago

the name can be Linda F. Green or even Linda Green or anything else but without digits..

lollo Over a year ago

don't matter if there is a space in the string .. my actually regex which is "/[A-Z]/" does return the name BUT ALSO the address "12012 BlaBla Xx" that i want to discard...

zessx Over a year ago

/^[A-Z]+[a-zA-Z]+( [A-Z]\.)? [A-Z]+[a-zA-Z]+$/ will accept Linda F. Green and Linda Green, but NOT linda green, Linda F Green, Linda f. green

zessx Over a year ago

Me neither ;) You're welcome, and please set this question as answered if you're done with.

|

walrii · Accepted Answer · 2012-06-02 00:25:33Z

0

preg_match will match if any part of the string matches the regular expression. If you want to test the whole string, use ^ and $ which represent the start and end of the string.

answered Jun 2, 2012 at 0:25

walrii

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2 Comments

jordanm Over a year ago

The "m" regex modifier to the regex will treat each \n as a new string.

Qtax Over a year ago

@jordanm, no, /m only changes what ^ and $ match.

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