how to replace string with result of function in Vim?

Question

I want to insert filename and line number into some places in the file. For example this line:

_debug('init');

I want to replace

:s/debug('/debug('(%current_filename_here%:%current_line_number_here%)\ /g

to get this

_debug('(filename.ext:88) init');

I try to use expand('%:t') to get filename and line(".") to get line number, but I don't know how to use it in replace expression.

How can I do this?

kev · Accepted Answer · 2012-06-06 09:19:07Z

8

You can use \=. For example:

:s@_debug('\zs@\=printf('(%s:%d) ', expand('%:t'), line('.'))@

When the {replacement} starts with "\=" it is evaluated as an expression,

edited Jun 6, 2012 at 9:19

answered Jun 6, 2012 at 9:10

kev

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3 Comments

Neka Over a year ago

I can not use Vim functions directly in expression, through printf only, right?

Amadan Over a year ago

You can use vim functions. @ is just a separator. It is customary to write the function as :s///, but :s### works as well, as does :s@@@...

kev Over a year ago

@Neka printf is a function in vim. You can use \='('.expand('%:t').':'.line('.').') ', as you can see, I use . to concatenate multiple expression.

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