MVC3: Access a property of an Object in the view

Question

in an ASP.NET MVC3 web application.

I have a view. the view has a IEnumerable model.

I need to loop through all the model's items and show the item.Name

The view:

@model IEnumerable<Object> 
@{
    ViewBag.Title = "Home";
}

@foreach (var item in Model)
{ 
    <div class="itemName">@item.Name</div>
}

In the controller, I use Linq to entities to get the list of objects from the database.

The Controller:

public ActionResult Index()
{
    IEnumerable<Object> AllPersons = GetAllPersons();
    return View(AllSurveys);
}

public IEnumerable<Object> GetAllPersons()
{
    var Context = new DataModel.PrototypeDBEntities();
    var query = from p in Context.Persons
                select new
                {
                    id = p.PersonsId,
                    Name = p.Name,
                    CreatedDate = p.CreatedDate
                };
    return query.ToList();
}

When I run I get this error:

 'object' does not contain a definition for 'Name' and no extension method 'Name' accepting a first argument of type 'object' could be found (are you missing a using directive or an assembly reference?)

How can I access the "Name" Property of the model items?

Thanks a lot for any help

Matthew Whited · Accepted Answer · 2012-06-06 19:55:13Z

3

Create a strong type for your method return.

public class MyObject {
    public int id {get;set;}
    public string Name {get;set;}
    public DateTime CreatedDate {get;set;}
}

public IQueryable<MyObject> GetAllPersons() 
{ 
    var Context = new DataModel.PrototypeDBEntities(); 
    var query = from p in Context.Persons 
                select new MyObject
                { 
                    id = p.PersonsId, 
                    Name = p.Name, 
                    CreatedDate = p.CreatedDate 
                }; 
    return query;
}

... Then update your view to reflect the new model ...

@model IQueryable<MyObject>

edited Jun 6, 2012 at 19:55

answered Jun 6, 2012 at 18:54

Matthew Whited

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Comments

YavgenyP · Accepted Answer · 2012-06-06 18:54:43Z

1

The easiest way would be to define a class Person, and to change your model/controller to work with IEnumerable<Person> instead of object.

answered Jun 6, 2012 at 18:54

YavgenyP

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Shyju · Accepted Answer · 2012-06-06 18:55:03Z

1

You probably need to do an explicit Casting

@(string) item.Name

or use dynamic type.

In the view, Change

@model IEnumerable<Object>

to

@model IEnumerable<dynamic>

answered Jun 6, 2012 at 18:55

Shyju

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jrummell · Accepted Answer · 2012-06-06 18:54:12Z

0

Your model type is IEnumerable<Object>, change it to IEnumerable<Person> so that you can access Person properties.

answered Jun 6, 2012 at 18:54

jrummell

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Dusty Lau · Accepted Answer · 2012-06-06 19:01:43Z

0

I could be wrong but you might try to use IEnumerable<dynamic> instead of IEnumerable<Object>

edited Jun 6, 2012 at 19:01

answered Jun 6, 2012 at 18:53

Dusty Lau

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