Is there a way to compare an integer against an array of integers? For instance, to determine if an int is larger than any of the array ints?
var array = [1, 2, 3, 4];
if(5 > array){
// do something
}
Update: I guess I meant, is 5 larger than the largest number in the array. Thanks!
You can use Math.max and apply
if (5 > Math.max.apply(Math, array)) {
// do something
}
Update: To explain as it works. It's described in the docs I linked but I will try to be more clear here:
Math.max returns the largest of zero or more numbers, so:
Math.max(1, 2, 3, 4) // returns 4
apply calls a function with a given 'this' value (the first argument) and arguments provided as an array (the second). so:
function sum(a, b) {
return a + b;
}
console.log(sum.apply(window, [2, 3])); // 5
Therefore, if you have an array of integers and you want to get the max, you can combine them to have:
console.log(Math.max.apply(Math, [1, 2, 3, 4])); // 4
Because it's exactly like have:
console.log(Math.max(1, 2, 3, 4));
The difference is you pass an array instead.
Hope it's more clear now!
Math in the apply. You can use this instead: console.log(Math.max.apply(null, [1, 2, 3, 4])); // 4var max = Math.max; console.log(max(1, 2, 3, 4)); but some implementation could expect that this (the context object) is Math and in your case it isn't. For example, in Firefox is perfectly valid have console.log.apply(null, [1, 2]); but it Chrome will raise an error unless you have console.log.apply(console, [1, 2]);. So in order to avoid possible error (now or in the future) is preferable use the exact equivalent.There is no good and readable built in way of doing it, but it can be done simply with:
var bigger = true;
for (var i =0; i < array.length; i++) {
if (5 <= array[i]) {
bigger = false;
// you can add here : break;
}
}
Sure, you could sort the array, take the last element, and see if your integer is greater than that. Or, you could loop through and check each one. Up to you. The loop is a more performant way.
//maybe check the bounds on this if you know it can be a blank array ever
var max = myArray[0];
for(var x = 0; x < myArray.length; x++) {
max = Math.max(max, myArray[x]);
}
if(500 > max) {
//do something
}
