Django url pattern matching

Question

I've been over this for too many hours now and I cannot see anymore what I'm doing wrong:

url(r'^baz/([a-z0-9]+)/([a-z0-9]+)/[0-9]/$', 'foobar.views.baz')

def baz(request, xxx, yyy, zzz):
    pass

And this is the actual URL being requested:

http://localhost:8000/baz/75ca0f5bf13d67895e23419c25f82e87f3f5f95f/f733dbf686cd51f911e533d5a351f81394c9db5c/0/

Django keeps throwing this error at me:

baz() takes exactly 4 arguments (3 given)

What am I doing wrong?

Matthias · Accepted Answer · 2012-06-15 10:34:29Z

6

You're missing the last block of parens in your regular expression.

url(r'^baz/([a-z0-9]+)/([a-z0-9]+)/([0-9])/$', 'foobar.views.baz')

With the parens Python will capture the [0-9] as a group and now you'll get all 3 parameters (+ the self) instead of 2.

answered Jun 15, 2012 at 10:34

Matthias

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1 Comment

Thanks Matthias! I actually had the parens in some earlier rev of that file!