I am a noob, How do I remove quotations and commas from my list? Or how do I "unstring"?
Without showing the dictionary (dic), the code I am using looks like this:
>>>import itertools
>>>list(itertools.product(dic[2], dic[3])
my results looks like this:
[('A', 'D'), ('A', 'E'), ('A', 'F'), ('B', 'D'), ('B', 'E'), ('B', 'F'), ('C', 'D'), ('C', 'E'), ('C', 'F')]
I would like them to look like this:
AD, AE, AF, BD, BE, BF,
You want to produce a string, so you can use string manipulation (in particular, the join method):
>>> import itertools
>>> a = ['A', 'B']
>>> b = ['D', 'E', 'F']
>>> print ', '.join(''.join(x) for x in itertools.product(a, b))
AD, AE, AF, BD, BE, BF
Actually you don't even need itertools, you could just use a nested comprehension:
>>> print ', '.join(x + y for x in a for y in b)
You can use join string method:
>>> import itertools
>>> p = list( itertools.product( ['a','b','c' ],['e','f','g'] ) )
>>> p
[('a', 'e'), ('a', 'f'), ('a', 'g'), ('b', 'e'), ('b', 'f'), ('b', 'g'), ('c', 'e'), ('c', 'f'), ('c', 'g')]
>>> ', '.join( a+b for (a,b) in p )
'ae, af, ag, be, bf, bg, ce, cf, cg'
import itertools
import sys
yourlist = list(itertools.product(dic[2], dic[3])
sys.stdout.write (yourlist[0][0] + yourlist[0][1])
for i in xrange (1, len(yourlist)):
sys.stdout.write (", " + yourlist[i][0] + yourlist[i][1])
Although other answers use the join() method (the correct and 'python' way to do it) I have given you a simple rough and tough solution so I don't kill your current lesson with you trying to figure out how the join() method works.
print statements?
stdout rather than using print()? Also, I don't feel join() is such a hard concept to get, so while I get what you were trying to do, I don't think it benefits anyone.print not print trailing whitespace after what you gave it as arguments.from __future__ import print_function and then use print(..., end="") if you are stuck with 2.6/2.7.stdout.write)What about this using list comprehension?
p = [('A', 'D'), ('A', 'E'), ('A', 'F'), ('B', 'D'), ('B', 'E'), ('B', 'F'), ('C', 'D'), ('C', 'E'), ('C', 'F')]
', '.join([''.join(i) for i in p])
and join() to concatenate strings gives:
AD, AE, AF, BD, BE, BF, CD, CE, CF
Alternatively, a generator expression would also work (thanks to @Nicklas B reminding me, for some reason list comprehension comes to my mind first):
', '.join(''.join(i) for i in p)
An alternate solution:
In [61]: l=[('A', 'D'), ('A', 'E'), ('A', 'F'), ('B', 'D'), ('B', 'E'), ('B', 'F'),
('C', 'D'), ('C', 'E'), ('C', 'F')]
In [62]: ', '.join(t[0]+t[1] for t in l)
Out[62]: 'AD, AE, AF, BD, BE, BF, CD, CE, CF'
