Issues with calling a JavaScript function from PHP

Question

I have created a form to upload a a newsletter into the database. I'm using the iFrame method to post the date without the page refresh and I'm displaying a nice jQuery dialog for the loading.

I am now having issues with closing that dialog when the upload is complete. All the tutorials I have read online say that I must just echo out the code like this:

<?php
  echo "<script type='text/javascript>uploadComplete();</script>";
?>

Now the JavaScript does run when I do something stupid to test like just echo out an alert, but when I try and call any function or just go straight to the jQuery to close the dialog it just says that the function is not defined. I can post my code if it is necessary, but it's pretty standard and I didn't think I would need to in this kind of example.

Any help would be appreciated! Thanks in advance.

Still haven't figured it out.. any other suggestions?

Nicholas Corin
– Nicholas Corin

2012-06-18 10:22:03 +00:00
Commented Jun 18, 2012 at 10:22 — Nicholas Corin
– Nicholas Corin, Commented Jun 18, 2012 at 10:22

mgraph · Accepted Answer · 2012-06-18 08:18:00Z

5

you forgot ' in the end of 'text/javascript'

echo "<script type='text/javascript'>uploadComplete();</script>";

NB : the type attribute is entirely unnecessary if the script is JavaScript

edited Jun 18, 2012 at 8:18

answered Jun 18, 2012 at 8:10

mgraph

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1 Comment

Nicholas Corin Over a year ago

Oh that's my bad, but the typo is fixed in my code and it doesn't work. But thanks!

Nikhil D · Accepted Answer · 2012-06-18 08:12:35Z

1

using just php

echo '<script type="text/javascript">'
   , 'jsfunction();'
   , '</script>';

escaping from php mode to direct output mode

<?php
// some php stuff
?>
<script type="text/javascript">
    jsFunction();
</script>

answered Jun 18, 2012 at 8:12

Nikhil D

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1 Comment

Nicholas Corin Over a year ago

I have tried both of these methods but it just wont find the function. And I have double checked the function names that they are correct.

Nicholas Corin · Accepted Answer · 2012-06-25 12:48:12Z

0

I eventually solved this by using the following code:

<?php
  echo "<script type='text/javascript>top.uploadComplete();</script>";
?>

The "top" keyword just solved all of my problems. I hope this helps whoever has the same issue I had!

answered Jun 25, 2012 at 12:48

Nicholas Corin

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