Syntax Problems of if Statement (php)

Question

I need a little help with an if statement in php. I'm trying to set a variable called offset according to a page that I am loading in WordPress. Here's the variable:

$offset = ($paged * 6);

What it does is it loads the first page, which is:

http://example.com/blog

and $offset is thus set to 0 because $paged is referring to the appending number on the URL. The second page, for example is:

http://example.com/blog/2/

which makes $offset set to 12. The problem is, I need the second page to define $offset as 6, the third page to define $offset as 12, etc. I tried using:

$offset = ($paged * 6 - 6)

which works except on the first page. On the first page it defines $offset as -6. SO, I wanted to create an if statement that says if $paged is equal to 0 then $offset is equal to 0, else $offset is equal to ($paged * 6 - 6).

I struggle with syntax, even though I understand what needs to be done here. Any help would be greatly appreciated. Thanks!

Emil Vikström · Accepted Answer · 2012-06-18 15:14:32Z

4

Because this is two different cases which cannot be easily integrated into a single formula, use an if statement:

if ($paged == 0)
  $offset = 0;
else
  $offset = ($paged - 1) * 6;

You can write this shorter using the ternary operator, but I think the above if statement is more readable:

$offset = ($paged == 0) ? 0 : ($paged - 1) * 6;

answered Jun 18, 2012 at 15:14

Emil Vikström

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Comments

Rifat · Accepted Answer · 2012-06-18 15:17:41Z

0

An alternative:

if($paged == 0) $paged = 1;
$offset = ($paged - 1) * 6;

or

$offset = ($paged) ? ($paged - 1) * 6 : 0;

answered Jun 18, 2012 at 15:17

Rifat

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2 Comments

jadkik94 Over a year ago

Pages 0 and 1 will be the same... :D

Rifat Over a year ago

@jadkik94 yep but what is the problem with that?

FatalError · Accepted Answer · 2012-06-18 15:17:46Z

0

you can use the following one line code

$offset = max(($paged - 1) * 6, 0);

answered Jun 18, 2012 at 15:17

FatalError

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4 Comments

Emil Vikström Over a year ago

The max() solution, while clever, may be confusing for a future maintainer.

FatalError Over a year ago

yes and no... it will also make him learn a simple trick. :-)

Emil Vikström Over a year ago

There's often a conflict between "simple tricks" and "maintainability". Otherwise everybody would be happy Perl coders.

FatalError Over a year ago

you are absolutely right. I am actually big fan of tricks and smart coding. Thats why I oftenly use ternary operator wherever I can. Some may prefer to use if-else instead of ternary.

jadkik94 · Accepted Answer · 2012-06-18 15:18:19Z

0

You could use: $offset = max(0, $paged * 6 -6);. Which takes the maximum of 0 and the other value. If the other value is negative, then 0 will be the result.

Now, to use an if statement, this is how you would do it:

$offset = $paged * 6 - 6;
if ($offset < 0) {
    $offset = 0;
}

Or:

if ($paged == 0) {
    $offset = 0;
} else {
    $offset = $paged * 6 - 6;
}

And you might want to use a ternary operator for this simple case:

$offset = ($paged == 0)? 0: ($paged * 6 - 6);

(which does the exact same thing as the above)

Note: You could replace 6*a-6 = 6*(a-1), but it's of no importance in the code, just readability...

answered Jun 18, 2012 at 15:18

jadkik94

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