jquery loop and compare values

Question

Is it possible to use jqueries each loop in this form to dissolve hyperlinks?

 $(document).ready(function() {
    var toExclude =['http://www.google.com', 'http://example'];
    $.each(toExclude, function(key, value) {

    $("a[href='+value+']").replaceWith(function(){
        var matches = value.match(/^https?\:\/\/([^\/?#]+)(?:[\/?#]|$)/i);
        var domain = matches && matches[1];
        return domain;
                });
            });
        });

on match all a href should be removed and just the a href text should be returned — lgt
– lgt, Commented Jun 19, 2012 at 9:16

Darin Dimitrov · Accepted Answer · 2012-06-19 09:36:23Z

5

$("a[href='+value+']")

should be:

$("a[href='"+value+"']")

Also you probably want to change only the href property => use the .attr method:

$("a[href='"+value+"']").attr("href", function() {
    // do your replace and return the new value of the href
    ...
});

edited Jun 19, 2012 at 9:36

answered Jun 19, 2012 at 9:13

Darin Dimitrov

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2 Comments

lgt Over a year ago

I'm getting an error on this Syntax error, unrecognized expression

Darin Dimitrov Over a year ago

Where are you getting this error? Could you show your code? Could you show a jsfiddle.net sample illustrating your problem?

Cranio · Accepted Answer · 2012-06-19 10:04:05Z

1

var toExclude = ['www.goo.com','www.dgoo.com'];

$.each(toExclude, function(i,e)
       {

           $("a[href^='"+e+"']").each(function (i,e) {$(e).replaceWith($(e).attr('href'));});
       }
);

edited Jun 19, 2012 at 10:04

answered Jun 19, 2012 at 9:27

Cranio

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2 Comments

Cranio Over a year ago

@lgt I'm supposing you want to replace each <a href='foo'>bar</a> with simply foo

lgt Over a year ago

yes that I would like to achieve if the a href is matching with one the values from array

ioleo · Accepted Answer · 2012-06-19 09:18:47Z

0

$('a[href="'+value+'"]').attr("href", function() {
    // do your replace and return the new value of the href

A little change in quote signs.. this allows you to also do

$('a[href$="'+value+'"]').attr("href", function() {
    // do your replace and return the new value of the href

and

$('a[href^="'+value+'"]').attr("href", function() {
    // do your replace and return the new value of the href

to match links beggining and ending with value

answered Jun 19, 2012 at 9:18

ioleo

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