Notepad++: Find and replace using regular expressions

Question

I apologize if it sounds dumb to you, but I need to find __( 'anyTextHere', 'foo' ) and replace all of the instances with 'anyTextHere'.

Basically, I just want to retain 'anyTextHere', then delete the rest.

Sample code:

    __( 'beach', 'foo' )
    __( 'summer', 'foo' )

then find:

    __( 'anyTextHere', 'foo' )

and when replaced with regular expressions, the result should be:

    'beach'
    'summer'

Thank you very much for your help!

stema · Accepted Answer · 2012-06-21 12:28:47Z

2

Search for

 __\( '([^']*)', 'foo' \)

and replace with $1

To be more general:

__\( '([^']*)', '[^']*' \)

and replace also with $1

answered Jun 21, 2012 at 12:28

stema

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2 Comments

@cblab I tested it in v6.1.2 works fine. Probably they changed it when they introduced PCRE regex in v6.0

@stema ah ok, my mistake, so. Good news, BTW.

Joey · Accepted Answer · 2012-06-21 12:28:39Z

2

You can replace

__\( '([']+), [^)]+)

by '\1'

answered Jun 21, 2012 at 12:28

Joey

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