Dynamically modifying/refreshing menu contents in PyGTK

Question

I am trying to implement a list of recently opened items in the menu of a GUI I am writing with PyGTK. I initialize the menu like so:

self.filemenu = gtk.Menu()

self.init_file_menu()

self.fileitem = gtk.MenuItem("File")
self.fileitem.set_submenu(self.filemenu)
menubar = gtk.MenuBar()
menubar.append(self.fileitem)
outerframe.pack_start(menubar, False, False)

def init_file_menu(self):
    for widget in self.filemenu.get_children():
        self.filemenu.remove(widget)

    openitem = gtk.MenuItem("Open")
    self.filemenu.append(openitem)
    openitem.connect("activate", self.open_file)

    self.filemenu.append(gtk.SeparatorMenuItem())

    for recentitem in self.settings['recentfiles']:
        item = gtk.MenuItem(os.path.basename(recentitem))
        self.filemenu.append(item)
        item.connect("activate", self.open_file, recentitem)
    self.filemenu.show()

self.settings['recentitems'] is a deque that is modified when opening a file; init_file_menu is then called again. My goal is to empty the menu, then repopulate it with the right items in the right order. This code works fine when populating the menu at startup. But for some reason while the calls to Menu.remove all work fine and empty the menu, the append calls do not re-add the items to it and it remains empty. If I call its get_children method, I see that they are all there internally, but the interface has not been updated to reflect this. How do I refresh the displayed menu and make the recent items list work as expected?

I would also accept direction on how to use the RecentChooserMenu widget if that is what I am looking for.

saeedgnu · Accepted Answer · 2012-06-22 18:22:36Z

5

Since gtk.Menu is a container, you need to .show every item after adding it to menu (Because you don't want to call menu.show_all() shortcut which shows the menu itself), so you do item.show() just after menu.append(item)

answered Jun 22, 2012 at 18:22

saeedgnu

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1 Comment

dpitch40 Over a year ago

Ah, right, that makes more sense than what I was trying. self.filemenu.show_all() also appears to work.

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