I have the following script1.sh:
#!/bin/bash
trap 'echo "Exit signal detected..."; kill %1' 0 1 2 3 15
./script2.sh & #starts a java app
./script3.sh #starts a different java app
When I do CTRL + C, it terminates script1.sh, but the Java Swing app started by script2.sh still stays open. How come it doesn't kill it?
I think something like this could work for you. However, as @carlspring mentioned you better have something similar in each script so you can catch the same interrupt and kill any missing child process.
Take whatever it
#!/bin/bash
# Store subproccess PIDS
PID1=""
PID2=""
# Call whenever Ctrl-C is invoked
exit_signal(){
echo "Sending termination signal to childs"
kill -s SIGINT $PID1 $PID2
echo "Childs should be terminated now"
exit 2
}
trap exit_signal SIGINT
# Start proccess and store its PID, so we can kill it latter
proccess1 &
PID1=$!
proccess2 &
PID2=$!
# Keep this process open so we can close it with Ctrl-C
while true; do
sleep 1
done
Well, if you're starting the script in background mode (using &), it's normal behavior for it to keep executing after the invoking script has exited. You need to get the process id of the second script by storing echo $$ to a file. Then make the respective script have a stop command which kills this process, when you invoke it.
