Regular expression to find the arguments in a function call

Question

I need to extract the arguments from a function Say, Function_1(arg1,agr2,....argn).

Is it possible to strip the arguments alone with out brackets.

I tried using $[\w,]*$ expression

Argument, as in passed to a function call, OR is it parameter of a function? — nhahtdh
– nhahtdh, Commented Jun 26, 2012 at 7:18

arnep · Accepted Answer · 2012-06-26 07:15:03Z

2

If you want to "catch" the matches you need to put braces around them:

 \(([\w,]*)\)

This way you will find everything arg1,arg2 in $1.

answered Jun 26, 2012 at 7:15

arnep

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1 Comment

Yeah.. much simpler , u will get it in the first group.

gout · Accepted Answer · 2012-06-26 07:13:27Z

1

use this Regular Expression (?<=[\w]*$)[\w,]*(?=$) to solve the purpose

answered Jun 26, 2012 at 7:13

gout

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What language have you tested this on?

The answer is using variable-width look-behind, which is only supported in C#. stackoverflow.com/questions/3159524/…