Calling Save dialog box from javascript

Question

I have a javascript function from which I need to call a controller action to return the filestream to the UI . I am not getting the open,save and save as dialog box. In the cshtml file I have following function:DownloadFile

var selectUrl = '@Url.Action("Download", "Controller")' + "/" + filedetails; 
$.post(selectUrl);

and in the controller I have the following code:

public ActionResult Download(string id)
return File(downloadStream, "application/octet-stream",fileName);

Please let me know is this the correct way of calling.

You dont see the dialog box, but what exactly happens when you call that javascript function.------------ Please edit your post and correctly use code tag. — Mohayemin
– Mohayemin, Commented Jun 29, 2012 at 11:08
On click of the button I want to call the ActionResult which returns File(downloadStream, "application/octet-stream",fileName); so that the user can see the open dialog box. — user1400915
– user1400915, Commented Jun 29, 2012 at 11:11
I understand what you want, I am asking what is happening now when you click the button? Nothing happens? — Mohayemin
– Mohayemin, Commented Jun 29, 2012 at 11:12
Nothing is happening ,its just executing and nothing is displayed in UI — user1400915
– user1400915, Commented Jun 29, 2012 at 11:16
Use var selectUrl = '@Url.Action("Download", "Controller", new {id=filedetails})' and tell me if it works. Apparently, you are not going to the correct url. Put a debug pointer in your Download Action to see if your request reach there. — Mohayemin
– Mohayemin, Commented Jun 29, 2012 at 11:27

Community · Accepted Answer · 2017-05-23 11:48:52Z

1

try this way :ActionResult

 public ActionResult Download(string id) 
    {
          var cd = new System.Net.Mime.ContentDisposition
                    {

                        FileName = "imagefilename",
                        Inline = false,
                    };
        Response.AppendHeader("Content-Disposition", cd.ToString());
        string contentType = "application/octet-stream";
          // you are downloadStream
        return File(downloadStream, contentType);
    }

link here

edited May 23, 2017 at 11:48

CommunityBot

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answered Jun 29, 2012 at 11:08

Tamkeen

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