How to pass a block to another in Ruby?

Question

Assuming I have the following proc:

a = Proc.new do
    puts "start"
    yield
    puts "end"
end

Also assuming I pass a to another method which subsequently calls instance_eval on another class with that block, how can I now pass a block onto the end of that method which gets yielded in a.

For example:

def do_something(a,&b)
    AnotherClass.instance_eval(&a) # how can I pass b to a here?
end

a = Proc.new do
    puts "start"
    yield
    puts "end"
end

do_something(a) do
    puts "this block is b!"
end

Output should of course should be:

start
this block is b!
end

How can I pass the secondary block to a in the instance_eval?

I need something like this for the basis of a Ruby templating system I'm working on.

possible duplicate of Trouble yielding inside a block/lambda — Ciro Santilli OurBigBook.com
– Ciro Santilli OurBigBook.com, Commented Oct 21, 2014 at 18:42

Linuxios · Accepted Answer · 2012-07-03 16:06:03Z

6

You can't use yield in a. Rather, you have to pass a Proc object. This would be the new code:

def do_something(a,&b)
    AnotherClass.instance_exec(b, &a)
end

a = Proc.new do |b|
    puts "start"
    b.call
    puts "end"
end

do_something(a) do
    puts "this block is b!"
end

yield is only for methods. In this new code, I used instance_exec (new in Ruby 1.9) which allows you to pass parameters to the block. Because of that, we can pass the Proc object b as a parameter to a, which can call it with Proc#call().

answered Jul 3, 2012 at 16:06

Linuxios

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David · Accepted Answer · 2012-07-03 16:25:11Z

0

a=Proc.new do |b|
    puts "start"
    b.call
    puts "end"
end
def do_something(a,&b)
  AnotherClass.instance_eval { a.call(b) }
end

answered Jul 3, 2012 at 16:25

David

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1 Comment

Linuxios Over a year ago

That wont work. instance_eval doesn't capture variables in the same way as normal blocks do.

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