jQuery - How to select specific element inside text?

Question

I have some text lines like that :

vt_wildshade2^508^508
vt_ailleurs2^1188^1188
...
vt_high2^13652^13652

Is it possible to select with jQuery the last numbers after the second "^" and remove the other part ?

ie keeping the last number of each lines like this :

508
1188
...
13652

I know how to select class / id / specific text but i hang up here. thank in advance

i assume this is plain text within HTML tags? In that case? sounds like a job for regular expressions. Alternatively, use split('^') on the string and the last element of the array will contain your number — jackwanders
– jackwanders, Commented Jul 5, 2012 at 20:02

Austin · Accepted Answer · 2012-07-05 20:12:23Z

1

If the format will always be the same, you can use javascript's String.split(delimiter) method to split the string at the '^' into an array, which will return something like:

    ["vt_wildshade2", "508", "508"]

In this case, the following code would take the last bit from your line:

    var str = "vt_wildshade2^508^508";
    var numbers = str.split("^")[2];

For reference:

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String/split

If the format will not always be the same, it will be required to use regular expressions to find the data that you want in the format that you need it, as other answerers have explained.

Not sure how this data is coming in, could you clarify on how this data is displayed before the script is run?

edited Jul 5, 2012 at 20:12

answered Jul 5, 2012 at 20:05

Austin

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Comments

Ricardo Lohmann · Accepted Answer · 2012-07-05 20:21:34Z

1

var string = 'vt_wildshade2^508^508',
    number = string.match(/[0-9]+$/)[0];
console.log(number);

$: Matches end of string.
[0-9]: Matches numbers.
+: Matches the preceding 1 or more times.
*: Mathes the preceding 0 or more times.
You can change + to * if you are not sure if it has numbers in the end of the string, this case number will be an empty string.

Demo using +
Demo using *

Reference: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/RegExp

edited Jul 5, 2012 at 20:21

answered Jul 5, 2012 at 20:07

Ricardo Lohmann

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6 Comments

lbstr Over a year ago

+1 you could also add +('vt_wildshade2^508^508'.match(/[0-9]+$/)); to parse it to an number.

VisioN Over a year ago

@lbstr To be precise, + will transform string to numeric, while match returns array on success.

lbstr Over a year ago

but be careful with my comment above. match returns an array, so if it returns nothing you end up with +[], which returns 0. Could be undesirable...

lbstr Over a year ago

@VisioN thank you for the correction! I caught most of that right after I posted it, but you're exactly right: it is an important distinction that its a Number, not an int.

Ricardo Lohmann Over a year ago

@lbstr The problem is that if I parse as number I have to make sure the string has the number in the end, this case it'll return 0 as value.

|

artlung · Accepted Answer · 2012-07-05 20:06:46Z

0

IF you have:

vt_wildshade2^508^508

Say, from:

var theText = $('p').text();

So, equivalent to:

var theText = 'vt_wildshade2^508^508';

You can get the final "508" text with:

var finalNumber = theText.split('^')[2];

And if you need it to be a numer, something more like:

var finalNumber = (theText.split('^').length > 2) ? parseInt(theText.split('^')[2], 10) : -1;

If there is no 3rd number, the default is -1 in the code above.

answered Jul 5, 2012 at 20:06

artlung

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2 Comments

user1092395 Over a year ago

Another question : if i want to get the number AND the name like this "wildshade : 508" how can i do that ? In fact i want to get the name with the number, then passing all in a filter function to make a rank ? anyway thank a lot !

artlung Over a year ago

@user1092395 I don't see where the text "wildshade" would be coming from in your question. I suggest asking a whole new question since is sounds unrelated to the data you show in the current question.

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