XML Parser With Java Code

Question

I want to populate a Drop Down list via an XML File. I have crated the XML File already and the code i have written firstly to read the xml file and just give me the items from the xml file is compiliing but giving me errors when i want to run the code later.

public ArrayList readXML(){

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    DocumentBuilder db;

        try {
            db = dbf.newDocumentBuilder();

    Document dom;

        dom = db.parse("PVS_XML.xml");

    Element docEle = dom.getDocumentElement();

    NodeList nl = docEle.getElementsByTagName("item");
    System.out.println(((Node) nl).getNodeValue());

        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    return null;
}

Error Message:

java.lang.ClassCastException: com.sun.org.apache.xerces.internal.dom.DeepNodeListImpl cannot be cast to org.w3c.dom.Node
at de.sidion.pvsng.pages.InputPage.readXML(InputPage.java:222)
at de.sidion.pvsng.pages.InputPage.init(InputPage.java:255)
at de.sidion.pvsng.pages.InputPage.<init>(InputPage.java:183)
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:57)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)

Woody · Accepted Answer · 2012-07-06 11:34:39Z

3

You cant cast a node list to a node. Get the first element of the list if that is what you want

NodeList nl = docEle.getElementsByTagName("item");
...
((Node) nl).getNodeValue() <-- this

if you really want that, either go through the list or get an element of the list:

for(Node n : nl)
    System.out.println(n.getNodeValue());

EDIT

My mistake, it is not itterable, try to do it by size:

for(int i=0; i < nl.getLength(); i++)
{
   Node childNode = nl.item(i);
   System.out.println(childnode.getNodeValue());
}

However, I suspect this is still not what you want to do, as what you are getting are elements, and elements do not have values, they have text nodes that have values. Which means you need the child node (the text node). So you probably want something like

for(int i=0; i<nodeList.getLength(); i++)
{
   Element childElement = (Element)nodeList.item(i);
   NodeList innernodes = childElement.getChildNodes();

   System.out.println(innernodes.item(0).getNodeValue());
}

edited Jul 6, 2012 at 11:34

answered Jul 6, 2012 at 11:04

Woody

5,1502 gold badges26 silver badges29 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Woody Over a year ago

I would also say that the top line of the exception report clearly tells you this.

Pita Over a year ago

public ArrayList readXML(){ DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db; try { db = dbf.newDocumentBuilder(); Document dom; dom = db.parse("PVS_XML.xml"); Element docEle = dom.getDocumentElement(); NodeList nl = docEle.getElementsByTagName("item"); ((Node) nl).getNodeValue(); for(Node n: nl) { System.out.println(n.getNodeValue()); } } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } return null; }

Pita Over a year ago

done it as you said, but where it says for(Node n: nl) { it underlines nl and it says Can only iterate over an array or an instance of java.lang.Iterable

Collectives™ on Stack Overflow

XML Parser With Java Code

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related