is it possible to open a explorer window from powershell and store the path selected in the explorer, to a variable?
to open explorer window from powershell
PS C:> explorer
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6 Answers
Maybe this script is what you want:
Function Select-FolderDialog
{
param([string]$Description="Select Folder",[string]$RootFolder="Desktop")
[System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms") |
Out-Null
$objForm = New-Object System.Windows.Forms.FolderBrowserDialog
$objForm.Rootfolder = $RootFolder
$objForm.Description = $Description
$Show = $objForm.ShowDialog()
If ($Show -eq "OK")
{
Return $objForm.SelectedPath
}
Else
{
Write-Error "Operation cancelled by user."
}
}
Use as:
$folder = Select-FolderDialog # the variable contains user folder selection
1 Comment
Shay Levy
You need to move the assembly loading after the param block.
I found the use of reflection in the selected answer to be a little awkward. The link below offers a more direct approach
Copy and pasted relevant code:
Add-Type -AssemblyName System.Windows.Forms
$FolderBrowser = New-Object System.Windows.Forms.FolderBrowserDialog
[void]$FolderBrowser.ShowDialog()
$FolderBrowser.SelectedPath
Comments
The above did not work for me. Running Windows 7 with Powershell Version 2. I did find the following, which did allow the pop-up and selection:
Function Select-FolderDialog
{
param([string]$Description="Select Folder",[string]$RootFolder="Desktop")
[System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms") Out-Null
$objForm = New-Object System.Windows.Forms.FolderBrowserDialog
$objForm.Rootfolder = $RootFolder
$objForm.Description = $Description
$Show = $objForm.ShowDialog()
If ($Show -eq "OK")
{
Return $objForm.SelectedPath
}
Else
{
Write-Error "Operation cancelled by user."
}
}
Just in case others have the same issues.
1 Comment
Baodad
Works but has the issue of not showing the dialog in front sometimes.
Just wanted to post an addendum, I believe there is a pipe | missing from in-between:
[System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms")
and:
Out-Null
1 Comment
Eduard Malakhov
Missing in which answer / piece of code? As far as I can see, there is a pipe at least in the answer that's been accepted.
Here is a solution that opens explorer dialog window, asking user to select a folder. Then stores the folder path inside a variable named "path":
Add-Type -AssemblyName System.Windows.Forms
$browser = New-Object System.Windows.Forms.FolderBrowserDialog
$null = $browser.ShowDialog()
$path = $browser.SelectedPathode
Comments
Your code worked for me only after I have replaced ".SelectedPathode" with ".SelectedPath"
Add-Type -AssemblyName System.Windows.Forms
$browser = New-Object System.Windows.Forms.FolderBrowserDialog
$null = $browser.ShowDialog()
$path = $browser.SelectedPath
Here is also the documentation regarding the respective property - https://learn.microsoft.com/en-us/dotnet/api/system.windows.forms.folderbrowserdialog.selectedpath?view=net-5.0
