Is this the DRYest way to do it in ruby?
<% for item in @items %>
<%= n = n + 1 rescue n = 1 %>
<% end %>
which initializes "n" to '1" and increments it as the loop progresses (and prints it out) since this is in one my app's views
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3 Answers
You can use a ternary operator:
<% for item in @items %>
<%= n = n ? n+1 : 1 %>
<% end %>
But, depending on what you're trying to do, I'm guessing an each_with_index would be more appropriate
<% @items.each_with_index do |item, n| %>
<%= n %>
<% end %>
3 Comments
Zepplock
Ah nice, I guess the second option is what I was looking for.
Zepplock
Also is there a way to assign an initial value to "n"?
zaius
Assign an initial value and then increment by 1 each time? The index isn't a counter - it's an index. If you want to increase it by a fixed offset, just add it when you print: <%= n + 5 %>
You could also rely on ruby's nil coercion to an integer which results in zero.
<% for item in @items %>
<%= n = n.to_i + 1 %>
<% end %>
Comments
Um.
n = @items.size
2 Comments
Zepplock
No, @items.size is a constant (within a loop scope)
glenn mcdonald
Ah, I assume you mean that you're doing something [i]else[/i] with it in the loop, not shown in your example?