Remove part of string between two indexOf in javascript

Question

How can i remove from a string between two indexOf

i have this jsFiddle

here is my code :

 var x = "M 178.6491699876038 23.419570090792845 C 183.6491699876038 
23.419570090792845 186.47776067057902 30.902823043098138 190.3670728596699 
     41.19229585251793 L 194.25638504876076 51.48176866193772" ; 
  var c = x.indexOf('C') ; 
  var L = x.indexOf('L') ;
  var final = x.slice (c,L) ;
  console.log(final) ;

this code will result in returning the removed part of the string

QUESTION how can i return the original string after removing the part between C and L

Nevermind, from your wording, I thought you just wanted your oringinal string, which would of been in X, not your orginal string minus the middle. — Limey
– Limey, Commented Jul 20, 2012 at 12:06

Brandon · Accepted Answer · 2013-12-04 17:03:23Z

9

var c = x.indexOf('C') ; 
var L = x.indexOf('L') ;

var remaining = x.slice(0, c) + x.slice(L);

Fiddle:

http://jsfiddle.net/ePbCP/

edited Dec 4, 2013 at 17:03

answered Jul 19, 2012 at 17:52

Brandon

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3 Comments

GottZ Over a year ago

var remaining = x.slice(0, c-1) + x.slice(L-1, x.length); result: M 178.6491699876038 23.419570090792845 L 194.25638504876076 51.4817686619377

gen_Eric Over a year ago

@Jan-StefanJanetzky: That removes the 'L'. I don't think that is the desired result.

gen_Eric Over a year ago

@Jan-StefanJanetzky: Why is that better than what's posted in the answer?

adeneo · Accepted Answer · 2012-07-19 17:52:51Z

4

Just replace that part of the original string with nothing :

var x = "M 178.6491699876038 23.419570090792845 C 183.6491699876038 23.419570090792845 186.47776067057902 30.902823043098138 190.3670728596699 41.19229585251793 L 194.25638504876076 51.48176866193772" ; 
var c = x.indexOf('C') ; 
var L = x.indexOf('L') ;

var final = x.slice (c,L) ;
console.log(x.replace(final, ''));

FIDDLE

answered Jul 19, 2012 at 17:52

adeneo

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Comments

gen_Eric · Accepted Answer · 2012-07-19 17:54:12Z

2

You can use 2 substrings for this.

var c = x.indexOf('C') ; 
var L = x.indexOf('L') ;

var y = x.substring(0, c) + x.substring(L);

answered Jul 19, 2012 at 17:54

gen_Eric

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Comments

Daniel Li · Accepted Answer · 2012-07-19 17:52:44Z

1

Try:

var x = "M 178.6491699876038 23.419570090792845 C 183.6491699876038 23.419570090792845 186.47776067057902 30.902823043098138 190.3670728596699 41.19229585251793 L 194.25638504876076 51.48176866193772";
var c = x.indexOf('C');
var L = x.indexOf('L');
var final = x.substring(0, c) + x.substring(L, x.length);
console.log(final);

answered Jul 19, 2012 at 17:52

Daniel Li

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Comments

gen_Eric · Accepted Answer · 2012-07-19 17:56:27Z

1

You can replace the final string with empty string to get the remaining part.

var remaining = x.replace(final,'');

Live Demo

edited Jul 19, 2012 at 17:56

gen_Eric

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answered Jul 19, 2012 at 17:55

Adil

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