Parse query part from url

Question

I want to parse query part from url, this is my code to do this:

>>> from urlparse import urlparse, parse_qs
>>> url = '/?param1&param2=2'
>>> parse_qs(urlparse(url).query)
>>> {'param2': ['23']}

This code looks good, but "parse_qs" method loses query parameters like "param1" or "param1=". Can I parse query part with stantard library and save all parameters?

Does this answer your question? Retrieving parameters from a URL — Nick
– Nick, Commented Jun 26, 2022 at 4:02

Wilfred Hughes · Accepted Answer · 2014-02-11 12:22:17Z

54

You want:

from urlparse import parse_qs, urlparse

parse_qs(urlparse(url).query, keep_blank_values=True)
# {'param2': ['2'], 'param1': ['']}

edited Feb 11, 2014 at 12:22

Wilfred Hughes

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answered Jul 22, 2012 at 13:41

Jon Clements

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1 Comment

redacted Over a year ago

For Python 3 the imports are from urllib.parse import parse_qs, urlparse

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