I have multiple bash file. I want to write a master bash file which will include all required bash file in current directory. I tried like this
#!/bin/bash
HELPER_DIR=`dirname $0`
.$HELPER_DIR/alias
But I when I put following line in my $HOME/.bashrc
if [ -f /home/vivek/Helpers/bash/main.bash ]; then
. /home/vivek/Helpers/bash/main.bash
fi
I am getting error no such file ./alias. File alias is there. How can I include relative bash file ?
Use $( dirname "${BASH_SOURCE[0]}" ) instead.
I added these two lines two my ~/.bashrc:
echo '$0=' $0
echo '$BASH_SOURCE[0]=' ${BASH_SOURCE[0]}
and started bash:
$ bash
$0= bash
$BASH_SOURCE[0]= /home/igor/.bashrc
There is a difference between $0 and $BASH_SOURCE when you start a script with source (or .) or in ~/.bashrc.
You need to leave a space after the "dot"
. $HELPER_DIR/alias
$( dirname "${BASH_SOURCE[0]}" ) returns . if you invoke the script from the same directory or a relative path if you call it using a relative path such as ../myscript.sh.
I use script_dir=$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd ) to get the directory that the script is in.
Here's an example script to test this functionality:
#!/bin/bash
# This script is located at /home/lrobert/test.sh
# This just tests the current PWD
echo "PWD: $(pwd)"
# Using just bash source returns the relative path to the script
# If called from /home with the command 'lrobert/test.sh' this returns 'lrobert'
bash_source="$(dirname "${BASH_SOURCE[0]}")"
echo "bash_source: ${bash_source}"
# This returns the actual path to the script
# Returns /home/lrobert when called from any directory
script_dir=$( cd "$(dirname "${BASH_SOURCE[0]}")" && pwd)
echo "script_dir: ${script_dir}"
# This just tests to see if our PWD was modified
echo "PWD: $(pwd)"
