Json_encode() not working in PHP 5.1? [duplicate]

Question

Possible Duplicate:
How can I decode json in PHP 5.1?

I am using json_encode function it works fine in my localhost...when i moved to server it not working ...I googled and find out that its does not support 5.1 version ...I want to use this function .any other possibility?wheather i need to upgrade to 5.2 or wat?

Please see this thread stackoverflow.com/questions/2370968/… — Dr. Dan
– Dr. Dan, Commented Jul 27, 2012 at 8:49
json_encode works under 5.1 too (see de2.php.net/manual/en/function.json-encode.php PHP 5 >= 5.2.0, PECL json >= 1.2.0). I would tipp: your don't have pecl/json installed on your server — donald123
– donald123, Commented Jul 27, 2012 at 8:53
Do you know how old PHP 5.1 is? Apart from being slow and lacking many very important features, it also has known security vulnerabilities. Upgrade to PHP 5.3 or PHP 5.4. — NikiC
– NikiC, Commented Jul 27, 2012 at 9:00
Thnks guys i found my answer ....boutell.com/scripts/jsonwrapper.html — shanmugavel
– shanmugavel, Commented Jul 29, 2012 at 8:05

periklis · Accepted Answer · 2012-07-27 08:50:04Z

17

Here's what I've used successfully for php 5.1 (Taken from comments under http://www.php.net/json_encode):

/**
 * Supplementary json_encode in case php version is < 5.2 (taken from http://gr.php.net/json_encode)
 */
if (!function_exists('json_encode'))
{
    function json_encode($a=false)
    {
        if (is_null($a)) return 'null';
        if ($a === false) return 'false';
        if ($a === true) return 'true';
        if (is_scalar($a))
        {
            if (is_float($a))
            {
                // Always use "." for floats.
                return floatval(str_replace(",", ".", strval($a)));
            }

            if (is_string($a))
            {
                static $jsonReplaces = array(array("\\", "/", "\n", "\t", "\r", "\b", "\f", '"'), array('\\\\', '\\/', '\\n', '\\t', '\\r', '\\b', '\\f', '\"'));
                return '"' . str_replace($jsonReplaces[0], $jsonReplaces[1], $a) . '"';
            }
            else
            return $a;
        }
        $isList = true;
        for ($i = 0, reset($a); $i < count($a); $i++, next($a))
        {
            if (key($a) !== $i)
            {
                $isList = false;
                break;
            }
        }
        $result = array();
        if ($isList)
        {
            foreach ($a as $v) $result[] = json_encode($v);
            return '[' . join(',', $result) . ']';
        }
        else
        {
            foreach ($a as $k => $v) $result[] = json_encode($k).':'.json_encode($v);
            return '{' . join(',', $result) . '}';
        }
    }
}

answered Jul 27, 2012 at 8:50

periklis

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2 Comments

shanmugavel Over a year ago

will it work perfect perikiles...?

periklis Over a year ago

Well I've used it a lot and for many years without a problem, but I can't tell 100% for sure. Upgrading to php 5.2+ is the preferred solution

Mihai Stancu · Accepted Answer · 2012-07-27 08:50:25Z

2

Yes json_encode is available in PHP 5 >= 5.2.0, you must either upgrade (recomended) or find a library that implements the functionality.

answered Jul 27, 2012 at 8:50

Mihai Stancu

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Comments

thedom · Accepted Answer · 2012-07-27 08:50:33Z

2

Take a look at http://de.php.net/json_encode in the comments. Some people provided a PHP-written function which does the same. Only the performance will (most likely) not be as good as the native one ;-).

answered Jul 27, 2012 at 8:50

thedom

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