How to deserialize xml nodes with a different name into a list

Question

I want to deserialize an xml file using c#.

the file has this form:

<parent>
   <TotProd Name="Total Produce Kwh">
       <Time value="00:00:00">10</Time>
       <Time value="00:30:00">10</Time>
        ............ 
   </TotProd>
   <ProdToNet Name="Produce to Net (iec)">
       <Time value="00:00:00">10</Time>
       <Time value="00:30:00">10</Time>
        ...........
   </ProdToNet> .....
</parent>

I want to deserialize all child elements of parent into a List<Myclass> with TotProd/ProdToNet as a property of Myclass.

How can i do this.

Provide your class details also..

Manish Parakhiya
– Manish Parakhiya

2012-07-31 08:44:01 +00:00
Commented Jul 31, 2012 at 8:44 — Manish Parakhiya
– Manish Parakhiya, Commented Jul 31, 2012 at 8:44

Kirjava · Accepted Answer · 2022-02-03 19:55:22Z

4

You can use a common class for both elements, if they have the same structure:

public class Time{
    [XmlAttribute]
    public string value {get; set; }
    [XmlText]
    public string Text {get;set;} // this will hold the innerText value ("10") of <Time>
}

public class Prod{

    [XmlAttribute]
    public string Name {get; set; }
    [XmlElement("Time")]
    public List<Time> Time {get; set; }
}

[XmlRoot("parent")]
public class Parent{
    [XmlElement(ElementName="ProdToNet", Type=typeof(Prod))]
    [XmlElement(ElementName="TotProd", Type=typeof(Prod))]
    public List<Prod> {get; set;}
}

UPDATE: The Time:value seems like a TimeSpan duration object, so it can be presented as:

public class Time{
    [XmlIgnore]
    public TimeSpan _duration;

    [XmlAttribute(DataType = "duration")]
    public string value
        get
        {
            return XmlConvert.ToString(this._duration);
        }

        set
        {
            this._duration = XmlConvert.ToTimeSpan(value);
        }
    }

edited Feb 3, 2022 at 19:55

Kirjava

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answered Jul 31, 2012 at 8:47

Tisho

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2 Comments

Daniel Over a year ago

Thanks. I also had to add XmlChoiceIdentifier attribute as displayed here "msdn.microsoft.com/en-us/library/…". it would be nice if it was possible to deserialize all child elements to a list even without know the name of the elements in advance.

Tisho Over a year ago

You can use a [XmlAnyElement] attribute to handle all elements without knowing their names, and then just deserialize them manually: msdn.microsoft.com/en-us/library/…

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