Preg_replace dynamic

Question

Keys, and values mysql.

$valores[$codigo] = "<img src=\"template/" . $template . "/smiles/" . $smile . "\" border=\"0\"/>";
$arrayKeys  =   array_keys($valores);
$arrayValues    =   array_values($valores);
return preg_replace($arrayKeys, $arrayValues, $coment);

error, Warning: preg_replace() [function.preg-replace]: No ending delimiter ':' found.

What is $codigo? what is $coment? What do you want to do? I don't understand the question. Por los nombres de las variables supongo que hablas español. Creo que no se está entendiendo qué es lo que quieres hacer realmente. Creo que deberías reformular la pregunta explicando un poco más. — Curlas
– Curlas, Commented Aug 2, 2012 at 10:50

Oussama Jilal · Accepted Answer · 2012-08-02 10:51:31Z

1

You may want to use str_replace() instead.

Edit :

You just need to replace preg_replace by str_replace :

return str_replace($arrayKeys, $arrayValues, $coment);

See the documentation here str_replace()

edited Aug 2, 2012 at 10:51

answered Aug 2, 2012 at 10:40

Oussama Jilal

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Mihai Matei · Accepted Answer · 2012-08-02 10:48:54Z

0

preg_replace() - Perform a regular expression search and replace

If I understand correctly you want to replace :) with smiles images so you can do that like this:

<?php
    $search = array(":))",":)");
    $replace  = array("<img src=\"template/" . $template . "/smiles/laugh.jpg\" />","<img src=\"template/" . $template . "/smiles/smile.jpg\" />");
    str_replace($search, $replace, $comment);
?>

answered Aug 2, 2012 at 10:48

Mihai Matei

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