I've been messing around with Django and the Django ORM at home, and I've got to say, I feel it is one of the best out there in terms of ease of use.
However, I was wondering if it was possible to use it in "reverse".
Basically what I would like to do is generate Django models from an existing database schema (from a project that doesn't use django and is pretty old).
Is this possible?
Update: the database in question is Oracle
Yes, use the inspectdb command:
inspectdb
Introspects the database tables in the database pointed-to by the DATABASE_NAME setting and outputs a Django model module (a models.py file) to standard output.
Use this if you have a legacy database with which you'd like to use Django. The script will inspect the database and create a model for each table within it.
As you might expect, the created models will have an attribute for every field in the table. Note that inspectdb has a few special cases in its field-name output:
[...]
dev version (with more emphasize ?? maybe not..)
(Django 1.7.1) Simply running python manage.py inspectdb will create classes for all tables in database and display on console.
$ python manage.py inspectdb
Save this as a file by using standard Unix output redirection:
$ python manage.py inspectdb > models.py
(This works for me with mysql and django 1.9)
I have made a reusable app based on django's inspectdb command utility, Django Inspectdb Refactor.
This breaks models into different files inside models folder from a existing database. This helps managing models when they become large in number.
You can install it via pip:
pip install django-inspectdb-refactor
Then register the app in settings.py as inspectdb_refactor
After this you can use it from command line as :
python manage.py inspectdb_refactor --database=your_dbname_defined_in_settings --app=your_app_label
This will successfully create models folder with all the tables as different model files inside your app. For example:
More details can be found here.
get_meta() missing 1 required positional argument: 'is_partition'. Using django 2.0