How to split a string with '#' in C#

Question

I tried to split a string wich contains these character #

domicilioSeparado = domicilio.Split(@"#".ToCharArray());

but every time the array contains just one member. I've tried a lot of combinations but anything seems to work, I also tried to replace the string with a blank space and it kinda works - the problem is that it remains a single string.

domicilio = domicilio.Replace(@"#", @" ");

How can I resolve this?

Complete code:

String[] domicilioSeparado;
String domicilio = dbRow["DOMICILIO"].ToString();

domicilioSeparado = domicilio.Split(@"#".ToCharArray());
if (Regex.IsMatch(domicilioSeparado.Last(), @"\d"))
{
    String domicilioSinNum = "";
    domicilioSinNum = domicilioSeparado[0];
    custTable.Rows.Add(counter, dbRow["CUENTA"], nombre,
        paterno, materno, domicilioSinNum, domicilioSeparado.Last(), tipoEntidad);
}

What's your string? The first example should work just fine. (Although '#' would be a lot better than @"#".ToCharArray().) — Ry-
– Ry- ♦, Commented Aug 9, 2012 at 18:35
Split with a '#' character should work just fine. Could you provide the input string you are using? — David W
– David W, Commented Aug 9, 2012 at 18:35
I don't suppose the characters are music sharp signs (U+266F) ♯ and not a standard number sign #? — vcsjones
– vcsjones, Commented Aug 9, 2012 at 18:37
@vcsjones: Not likely since the name domicilio implies an address of some sort. — Jeff Mercado
– Jeff Mercado, Commented Aug 9, 2012 at 18:40

Sean Cogan · Accepted Answer · 2012-08-09 19:21:17Z

6

If you just want to split a string on a delimiter, in this instance '#', then you can use this:

domicilioSeparado = domicilio.Split("#");

That should give you what you want. Your second attempt simply replaces all the characters '#' in the string with ' ', which doesn't seem to be what you want. Can we see the string you're trying to split? That might help explain why it's not working.

EDIT:

Ok, here's how I think your code should look, give this a shot and let me know how it goes.

List<string> domicilioSeparado = new List<string>();
String domicilio = dbRow["DOMICILIO"].ToString();

domicilioSeparado = domicilio.Split("#");

if (Regex.IsMatch(domicilioSeparado.Last(), @"\d"))
{
    String domicilioSinNum = "";
    domicilioSinNum = domicilioSeparado[0];
    custTable.Rows.Add(counter, dbRow["CUENTA"], nombre,
        paterno, materno, domicilioSinNum, domicilioSeparado.Last(), tipoEntidad);
}

edited Aug 9, 2012 at 19:21

answered Aug 9, 2012 at 18:44

Sean Cogan

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17 Comments

poz2k4444 Over a year ago

PRIVADA#9, it seems to split, because I print #9 but I cannot print PRIVADA alone

Sean Cogan Over a year ago

What does domcilioSeparado actually contain after that statement, though?

poz2k4444 Over a year ago

String domicilio = dbRow["DOMICILIO"].ToString(); domicilioSeparado = domicilio.Split(" ".ToCharArray());

carny666 Over a year ago

@user1588438 The array starts at 0 buy the way.

poz2k4444 Over a year ago

Well, I found the mistake, I was printing the whole string cause I didn't quit the last split, sorry for the troubles, thanks a lot my friend...

|

Rodrigo Guedes · Accepted Answer · 2012-08-09 19:08:00Z

1

Try this:

string[] domicilioSeparado;
domicilioSeparado = domicilio.Split('#');

Some notes: 1 - It is ('#'), instead of ("#"); 2 - Replace does not split a string, it only replace that part, keeping as a single string.

In case you want an example that includes the printing of the whole array:

string domicilio = "abc#def#ghi";
string[] domicilioSeparado;
domicilioSeparado = domicilio.Split('#');
for (int i = 0; i < domicilioSeparado.Length; i++)
{
   MessageBox.Show(domicilioSeparado[i]);
}

It will open a Message Box for each element within domicilioSeparado.

edited Aug 9, 2012 at 19:08

answered Aug 9, 2012 at 18:51

Rodrigo Guedes

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8 Comments

poz2k4444 Over a year ago

So, I won't have an array of strings?

Rodrigo Guedes Over a year ago

Yes, you will. If you print domicilioSeparado[1], for instance, you will get the second part of domicilio.

poz2k4444 Over a year ago

Cause I've done that, i didn't put the declaration of the string, but I think I could print domicilioSperadao[0] or domicilioSperadao[n], is it possible?

poz2k4444 Over a year ago

Well, then my problem isn't the split, my problem is to print just the first part of the string, insted it prints the complete string

poz2k4444 Over a year ago

Well, I found the mistake, I was printing the whole string cause I didn't quit the last split, sorry for the troubles, thanks a lot my friend...

|

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