How to call function pointer which take argument pointer?

Question

How to call with function pointer this function?

    double a(double *a){
    return *a;
}

I try this but without luck:

double (*p)(*double) = &a;

I didn't find much good tutorial for those purpose, can you refer me to some good link.

Kerrek SB · Accepted Answer · 2012-08-13 10:36:17Z

4

Like this:

double (*p)(double*) = &a;

As you can see, the function signature in the type of the function pointer is written in exactly the same way as in the actual function declaration (and you don't need to the arguments names).

edited Aug 13, 2012 at 10:36

answered Aug 13, 2012 at 10:25

Kerrek SB

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1 Comment

MSalters Over a year ago

The precise form used in the question (double *a) suggested that the * belongs to a, not double. That is probably the root cause.

Useless · Accepted Answer · 2012-08-13 10:28:37Z

0

Altered slightly so not everything is called a:

double deref(double *a)
{
    return *a;
}

double test()
{
    double (*deref_pointer)(double*) = deref;

    double value = 3.14;

    return deref_pointer(&value);
}

answered Aug 13, 2012 at 10:28

Useless

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