send form values with jquery

Question

I am trying to send specfic form data to a php update script to modify the stored values in our database, how do i pass the hidden value and the checked value.

<?php do { ?>
 <form>
<p> <?php echo $row_tasks['dept']; ?> / <?php echo $row_tasks['descrip']; ?> 
  <input type="checkbox" name="check" id="status" value="<?php echo $row_tasks['id']; ?   >">
  <input type="hidden"   id="tid" value="<?php echo $row_tasks['id']; ?>" />
  <input type="submit" name="update" id="update" value="Submit" />
 </p>
 </form>
 <?php } while ($row_tasks = mysql_fetch_assoc($tasks)); ?>
 <script>
  function showValues() {
  var str = $("form").serialize();
  $("#results").text(str);
 }
$(":checkbox, :radio").change(showValues);
$("select").change(showValues);
showValues();
 </script>
 <script type="text/javascript">
 $('form').submit(function() {
  alert($(this).serialize());
return false;
 });
 </script>
 <p><tt id="results"></tt></p

EliSherer · Accepted Answer · 2012-08-14 20:37:34Z

2

give the hidden input a name..

answered Aug 14, 2012 at 20:37

EliSherer

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3 Comments

user1599087 Over a year ago

ok redid the script and now the correct values show when on the alert step but the post data is equal to the last form generated, how do i have to only post the same values the serialize function has

user1599087 Over a year ago

user1599087 Over a year ago

<?php do { ?> <form method="post"> <p> <?php echo $row_tasks['dept']; ?> / <?php echo $row_tasks['descrip']; ?> <input name="sid" type="hidden" id="sid" value="1"> <input name="tid" type="hidden" id="tid" value="<?php echo $row_tasks['id']; ?>" /> <input type="submit" name="update" id="update" value="Submit" /> </p> </form> <?php } while ($row_tasks = mysql_fetch_assoc($tasks)); ?> <div class="success" style="display: none;">Task has been added.</div>

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