Simple jQuery Syntax and Concatenation within the jQuery Selectors

Question

Quick question, is this code possible?

function respond (primary_id) {
var answer = $('id_of_' + primary_id).val();    
}

I've tested it out but the error produced does not directly point to this line of code, but another that is using this variable answer so I can't be sure if this is causing the problem or something else. If this can't work, then what is an alternative?

Don't forget the # on id selectors =)

Chazbot
– Chazbot

2012-08-15 06:51:56 +00:00
Commented Aug 15, 2012 at 6:51 — Chazbot
– Chazbot, Commented Aug 15, 2012 at 6:51
Silly me. I forgot to add the #.

thank_you
– thank_you

2012-08-15 07:04:32 +00:00
Commented Aug 15, 2012 at 7:04 — thank_you
– thank_you, Commented Aug 15, 2012 at 7:04

HandiworkNYC.com · Accepted Answer · 2012-08-15 06:51:07Z

3

$('id_of_' + primary_id)

Would point to all elements:

<id_of_xxx>

Which don't exist in any version of HTML I've seen...

If you're looking for an element with that ID,

$('#id_of_' + primary_id)

Would be the way to go.

Also, don't forget to return the value:

function respond (primary_id) {
     var answer = $('id_of_' + primary_id).val();    
     return answer;
}

answered Aug 15, 2012 at 6:51

HandiworkNYC.com

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Comments

Nishu Tayal · Accepted Answer · 2012-08-15 07:01:03Z

2

You can find it very easily on http://api.jquery.com/id-selector/

Here, you should use '#' before the element Id like this.

function respond (primary_id) {
      var answer = $('#id_of_' + primary_id).val();    
}

answered Aug 15, 2012 at 7:01

Nishu Tayal

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Comments

Akshat Jiwan Sharma · Accepted Answer · 2012-12-11 19:16:47Z

1

Well if you are selecting an element based on an id it should be preceded by a # so your code should be

var answer = $('#id_of_' + primary_id).val();

edited Dec 11, 2012 at 19:16

answered Aug 15, 2012 at 6:53

Akshat Jiwan Sharma

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