what javascript prototype.constructor for? [duplicate]

Question

Possible Duplicate:
How does JavaScript .prototype work?

Here is the inheritance structure I setup for testing:

function A() {
    this.a = 1;
}

function B() {
    this.b = 2;
}

B.prototype = new A();
//B.prototype.constructor = B;

Below is what I tried in Chrome's JavaScript Console:

>var b = new B;
>b instanceof A
true

>B.prototype.constructor
function A() {
    this.a = 1;
}

My question is what's the purpose to setup B.prototype.constructor = B? Which I've already commented out? It doesn't seem to break the inheritance.

Thanks in advance.

stackoverflow.com/questions/541204/…

mattnull
– mattnull

2012-08-15 18:01:57 +00:00
Commented Aug 15, 2012 at 18:01 — mattnull
– mattnull, Commented Aug 15, 2012 at 18:01

Community · Accepted Answer · 2017-05-23 10:24:39Z

0

B.prototype.constructor = B results in instanceof' giving the expected results, but there are better ways of doing that. There is some discussion of this at: Convention for prototype inheritance in JavaScript

edited May 23, 2017 at 10:24

CommunityBot

11 silver badge

answered Aug 15, 2012 at 18:04

Erin Stanfill

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