Creating a flat list from return values of a recursive python function

Question

I am trying to compare two directories using the dircmp function in python

def cmpdirs(dir_cmp):
    for sub_dcmp in dir_cmp.subdirs.values():
        cmpdirs(sub_dcmp)
    return dir_cmp.left_only, dir_cmp.right_only, dir_cmp.common_files

if __name__ == '__main__':
    dcmp = dircmp('dir1', 'dir2')
    result = list(cmpdirs(dcmp))

I am trying to get a result like:

([file1,file2],[file3,file4],[file5,file6])

What is the best way to do this?

Have you tried changing return to yield ?

Jon Clements
– Jon Clements

2012-08-16 23:20:29 +00:00
Commented Aug 16, 2012 at 23:20 — Jon Clements
– Jon Clements, Commented Aug 16, 2012 at 23:20
I did, but the result was not a tuple of 3 lists.

arjunurs
– arjunurs

2012-08-16 23:35:23 +00:00
Commented Aug 16, 2012 at 23:35 — arjunurs
– arjunurs, Commented Aug 16, 2012 at 23:35

Eric Hulser · Accepted Answer · 2012-08-16 23:20:43Z

1

Never used dircmp before...but I think this should work looking at your code...

def cmpdirs(dir_cmp):
    # make copies of the comparison results
    left   = dir_cmp.left_only[:]
    right  = dir_cmp.righ_only[:]
    common = dir_cmp.common_files[:]

    for sub_dcmp in dir_cmp.subdirs.values():
        sub_left, sub_right, sub_common = cmpdirs(sub_dcmp)

        # join the childrens results
        left   += sub_left
        right  += sub_right
        common += sub_common

    # return the merged results
    return (left, right, common)

if __name__ == '__main__':
    dcmp   = dircmp('dir1', 'dir2')
    result = cmpdirs(dcmp)

answered Aug 16, 2012 at 23:20

Eric Hulser

4,04223 silver badges20 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Creating a flat list from return values of a recursive python function

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related