How to store and retrive Arrays in NSMutableArray

Question

Hello friends I want to store NSMutableAray's in NSMutableAray and want to retrieve it.I'm able to store it but could not access it. my code is below:

NSMutableArray *muteArray;
NSMutableArray *muteArray_Master;
NSMutableArray *mutArrar_Level1;            


NSArray *Children = [dictionary objectForKey:@"Children"];

if (Children.count > 0) {
    muteArray = [NSMutableArray arrayWithArray:Children];
}

muteArray_Master= [[NSMutableArray alloc] init];
mutArrar_Level1= [[NSMutableArray alloc] init];



[muteArray_Master addObject:muteArray]; // muteArray_Master array added one object successfully 

i = [muteArray_Master count]; // Here I have i=1

mutArrar_Level1 = [NSMutableArray arrayWithArray:[muteArray_Master objectAtIndex:i-1]]; // But here mutArrar_Level1 not producing correct data.still it is with 0 objects

So my requirement is to store more than one NSMutableArray's in NSMutableArray and access all in another.

Thanks Deepak R

Johannes Fahrenkrug · Accepted Answer · 2012-08-21 11:51:05Z

4

First off, I'm afraid to tell you that you need to work on your variable names. See https://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/CodingGuidelines/CodingGuidelines.html#//apple_ref/doc/uid/10000146-SW1

Anyhow, here's how you add multiple arrays to an array:

NSMutableArray *parentArray = [[NSMutableArray alloc] init];

for (int i = 0; i < 10; i++) {
    NSArray *childArray = [NSArray arrayWithObjects:
        [NSString stringWithFormat:@"a-%i", i], 
        [NSString stringWithFormat:@"b-%i", i], 
        [NSString stringWithFormat:@"c-%i", i],
        nil];

    [parentArray addObject:childArray];
}

And this is how you'd access all of them again:

for (int i = 0; i < 10; i++) {
    NSArray *childArray = [parentArray objectAtIndex:i];
    NSLog(@"Child Array %i", i);

    for (NSString *item in childArray) {
        NSLog(@"  Item: %@", item);
    }
}

Really easy :)

edited Aug 21, 2012 at 11:51

answered Aug 21, 2012 at 11:18

Johannes Fahrenkrug

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2 Comments

Deepak R Over a year ago

Thanks buddy and sorry about my variable naming.

Johannes Fahrenkrug Over a year ago

No problem. You'll just do yourself and others on your team a favor if you adhere to the naming conventions. Also, please don't forget to upvote and accept answers.

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