php modify expression return value with one boolean var

Question

This might sound naive, but in PHP, is it possible modify the outcome of an expression with one boolean value?

for example:

if(expression)
     //execute code

now, how can i do this?

if(!expression)
    //execute code

with the control of another boolean?

like:

$bool = true;
if( ($bool? :!)expression ) // if($bool) => !expresion ; if(!$bool) => expression 
    //execute code

so basically i want to have the have !expression when $bool is true and expression when $bool is false

i do know i can :

$bool ? !expression : expression

but it has the same expression twice...

Niet the Dark Absol · Accepted Answer · 2012-08-21 16:26:26Z

2

So basically you want to pass the test if $bool is true or expression is true, but not both. Textbook definition of XOR:

if( $bool xor expression)
    // execute code

answered Aug 21, 2012 at 16:26

Niet the Dark Absol

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Comments

deceze · Accepted Answer · 2012-08-21 16:23:33Z

1

if (expression == $bool)

or maybe

if (expression != $bool)

answered Aug 21, 2012 at 16:23

deceze♦

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Comments

Guillaume Alouege · Accepted Answer · 2012-08-21 16:41:12Z

1

I'm not sure i understand you but you can store the result of the expression in variable:

<?php
    $bool = false;
    $result = (1 == 2 || 1 == 1);
    if ($bool && !$result) {
    //do stuff
    echo '1';
    } else if (!$bool && $result) {
    //other stuff
    echo '2';
    } else {
    echo '3';
    }
?>

or maybe

$bool = false;
$result = (1 == 2 || 1 == 1);
$newVar = ($bool ? !$result : $result);

Or use eval but it's a little bit tricky.

edited Aug 21, 2012 at 16:41

answered Aug 21, 2012 at 16:34

Guillaume Alouege

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