How to write an OpenCL function

Question

I'm new to OpenCL and I'm trying to implement a simple function in OpenCL. The function is supposed to be called from a kernel function.

void swap(int *a, int *b)
{
    int *temp = a;
    b = a;
    a = temp;
}

However upon calling it, the swap doesn't work.

Is there a way to pass parameters by reference?

Lubo Antonov · Accepted Answer · 2012-08-21 16:45:47Z

4

The way you have written the function, it is not doing anything. You are just assigning the pointers around. You need to have this:

void swap(int *a, int *b)
{
    int temp = *a;
    *a = *b;
    *b = temp;
}

Reference parameters are not allowed, as far as I recall.

answered Aug 21, 2012 at 16:40

Lubo Antonov

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1 Comment

surely you mean *a=*b; *b=temp;