Access JSON output with spaces

Question

If a JSON string has spaces in its name "Some Items" (is there a more accurate term for this?), how do you access it in PHP after using json_decode($json_string) on it? Is this name even required for data returned from an API?

JSON String

{"Some Items":[{"post_id":"1284"},{"post_id":"1392"},{"post_id":"1349"}]}

These doesn't work

$data = json_decode($json_string);
$data = $data->"Some Items";    // invalid PHP
$data = $data["Some Items"];    // Cannot use object of type stdClass as array

possible duplicate of Error when get value from json_decode() in php?. Also see example #2 in the manual for json_decode. — mellamokb
– mellamokb, Commented Aug 22, 2012 at 14:33

FtDRbwLXw6 · Accepted Answer · 2012-08-22 14:35:52Z

6

You need to use curly brace ($object->{'...'}) syntax:

$data->{'Some Items'}

answered Aug 22, 2012 at 14:35

FtDRbwLXw6

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Vassilis Barzokas · Accepted Answer · 2012-08-22 14:35:38Z

2

Try this

$data->{'Some Items'};

answered Aug 22, 2012 at 14:35

Vassilis Barzokas

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thedom · Accepted Answer · 2012-08-22 14:36:24Z

2

Try that

<?php
$json = '{"Some Items":[{"post_id":"1284"},{"post_id":"1392"},{"post_id":"1349"}]}';
$decoded = json_decode($json);

// for example
echo($decoded->{"Some Items"}[0]->post_id);
?>

answered Aug 22, 2012 at 14:36

thedom

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wbit · Accepted Answer · 2012-08-22 14:50:17Z

1

If you don't like the curly braces idea you can use the dynamic accessor business:

$someitems = "Some Items";
var_dump($data->$someitems);

Or, you could cast $data to an array and use the square brackets:

$data = (array)json_decode($json_str);
var_dump($data['Some Items']);

json_decode has a switch so you don't need to use casting.

$data = json_decode($json_str, true);
var_dump($data);

answered Aug 22, 2012 at 14:50

wbit

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