split string by char C#

Question

I have a string that contain the following text:
[l=9;f=0;r=5;p=2]
There may be more than one:
[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]

I want to get the array of strings(for second example):

[l=9;f=0;r=5;p=2]
[l=9;f=0;r=6;p=2]

I tried this but it split not correctly:

Regex.Split(seat, "(?=])");

PS. regexp not mandatory.

U need to make it with Regex syntax? show us result you want to get — Harry89pl
– Harry89pl, Commented Aug 28, 2012 at 10:51
@harry180: the result shows in question, I want to get array — user1260827
– user1260827, Commented Aug 28, 2012 at 10:52
1 dimensional array or 2 dimensional array? or maybe you want a Dictionary<string,int>? — Harry89pl
– Harry89pl, Commented Aug 28, 2012 at 11:00

L.B · Accepted Answer · 2012-08-28 10:56:09Z

8

string input = "[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]";
var list = Regex.Matches(input, @"\[.+?\]")
            .Cast<Match>()
            .Select(m => m.Value)
            .ToList();

answered Aug 28, 2012 at 10:56

L.B

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1 Comment

user1260827 Over a year ago

@chridam: Yes, of course. Just SO say after 5 minutes, please.

Arif Eqbal · Accepted Answer · 2012-08-28 11:12:43Z

3

The below pattern might help you use the Split option of Regex

string input = "[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]";
string pattern = @"(?<=\]);";
Regex regex = new Regex(pattern);
string[] data = regex.Split(input);

answered Aug 28, 2012 at 11:12

Arif Eqbal

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Comments

g45rg34d · Accepted Answer · 2012-08-28 10:53:18Z

0

"[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]".Split(new string[] { "];" }, StringSplitOptions.None)

And then append "]" back to each item in the array...

Ugly but should work.

answered Aug 28, 2012 at 10:53

g45rg34d

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3 Comments

JleruOHeP Over a year ago

You should mention that then OP will need to add ] for his elements inside array

user1260827 Over a year ago

@niaher: no the first element will be equal [l=9;f=0;r=5;p=2

g45rg34d Over a year ago

You're right, so appending the "]" should do the trick.. Not the most elegant solution of course.

Huusom · Accepted Answer · 2012-08-28 11:11:59Z

Why don't you use regex capturing?

The pattern \[l=(\d);f=(\d);r=(\d);p=(\d)\] will capture the values in each array.

Example:

private static IEnumerable<dynamic> Match(string text)
{
    return Regex.Matches(text, @"\[l=(\d);f=(\d);r=(\d);p=(\d)\]")
        .Cast<Match>()
        .Where(m => m.Success)
        .Select(m => new { l = m.Groups[1].Value, f = m.Groups[2].Value, r = m.Groups[3].Value, p = m.Groups[4].Value });
}

static void Main(string[] args)
{
    foreach (var result in Match("[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]"))
        Console.Out.WriteLine("Setting: {0}, {1}, {2}, {3}", result.l, result.f, result.r, result.p);

    foreach (var result in Match("[l=9;f=0;r=5;p=2]"))
        Console.Out.WriteLine("Setting: {0}, {1}, {2}, {3}", result.l, result.f, result.r, result.p);
}

Enigmativity · Accepted Answer · 2012-08-28 11:19:56Z

0

Here's a LINQ approach:

Func<string, string> process = s =>
    String.Format("[{0}]",
        String.Join("];[",
            s
                .Split('[')
                .Select(x => x.Split(']'))
                .SelectMany(x => x)
                .Where(x => x != "" && x !=";")));

At the very least it works. :-)

Use it like this:

var result = process("[l=9;f=0;r=5;p=2];[l=9;f=0;r=6;p=2]");

answered Aug 28, 2012 at 11:19

Enigmativity

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Comments

Mark Reed · Accepted Answer · 2012-08-28 11:26:07Z

0

In your code:

Regex.Split(seat, "(?=])");

Seems like you're just missing the actual semicolon, and a backslash for the brakcet, from your regex. This works:

 string[] data = Regex.Split(seat, ";(?=\\[)");

answered Aug 28, 2012 at 11:26

Mark Reed

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