Java - RandomAccessFile() format issue

Question

My problem is when I get the data from a text file it seems to be in the wrong encoding or somthing. I dont know how to get around this issue sorry. Thanks in advance. Here is the code.

private static String readLogFile(String path, File f) throws IOException {
    if (f.exists()){
    String data;
        try (RandomAccessFile raf = new RandomAccessFile(f, "rw")) {
            char ch = raf.readChar();
            raf.seek(f.length());
            String dataCh = String.valueOf(ch);
            data = dataCh.toString();
            System.out.println(data);
        }
        return data;
    }

    else{
        String data = "";
        return data;
    }
}

Why the seek to EOF? Why are you calling toString() on a String? Why aren't you closing the file? WHy are you using a RandomAccessFile at all when you are just reading the start of it? — user207421
– user207421, Commented Aug 29, 2012 at 5:18
I have dumped this code as it had to many errors and now i am using FileInputStream . But yes the code about is terrible. — Nick
– Nick, Commented Aug 29, 2012 at 6:53

MadProgrammer · Accepted Answer · 2012-08-29 02:38:57Z

1

From the Java Docs

This method blocks until the two bytes are read, the end of the stream is detected, or an exception is thrown.

Note, "two bytes are read"

Because Java supports Unicode character's the stream is automatically assuming that reading a character from the stream needs to produce a Unicode character.

Try char ch = (char)raf.readByte(); instead

answered Aug 29, 2012 at 2:38

MadProgrammer

348k22 gold badges243 silver badges379 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Java - RandomAccessFile() format issue

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related