java search for a particular word in a string

Question

I have string like:

This.is.a.great.place.too.work.

(or)

This/is/a/great/place/too/work/

I want to see if this string has the word "place".

If they are word in a string I used contains("place"). as this is all one string I tried split but it is giving syntax error . can you please let me know how to get it?

string.contains("place") works
String.split(".").contains("place")   Error

"it is giving syntax error" Copy/paste the error as an edit to the question. Use code formatting. To do that, select the sample and click the {} button above the messaged posting/editing form. — Andrew Thompson
– Andrew Thompson, Commented Sep 6, 2012 at 6:03

RP- · Accepted Answer · 2012-09-06 06:10:16Z

2

use string.split("\\.").contains("place") this should work. .(dot) is a reserved character in regular expression, You need to escape that by using \\..

answered Sep 6, 2012 at 6:10

RP-

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Comments

Jason · Accepted Answer · 2012-09-06 06:11:42Z

2

Try to split with "//."

    String string = "This.is.a.great.place.too.work.";
    System.out.println(string.split("\\.")[0]);

answered Sep 6, 2012 at 6:11

Jason

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Comments

Kumar Vivek Mitra · Accepted Answer · 2012-09-06 06:33:27Z

1

Try it simply like this.......

String s = "This/is/a/great/place/too/work/";
String ss = "This.is.a.great.place.too.work";

System.out.println(s.contains("place"));
System.out.println(ss.contains("place"));

answered Sep 6, 2012 at 6:33

Kumar Vivek Mitra

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MaVRoSCy · Accepted Answer · 2012-09-06 06:05:02Z

1

you can use

String str = "This.is.a.great.place.too.work.";
boolean exists = str.contains("place");

This checks to find the word place in a String and returns true if found, false if not

answered Sep 6, 2012 at 6:05

MaVRoSCy

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1 Comment

The Learner Over a year ago

mine is a string like: This.is.a.great.place.too.work. so this wil not work with out split

CloudyMarble · Accepted Answer · 2012-09-06 06:09:14Z

1

you dont need to split the string in order to use the containts methode.

string str = "This.is.a.great.place.too.work.";

boolean found = str.contains("substring"); // should return true or false

Alternative you can use the:

str.indexOf("substring") > 0 to determine if the substring is in the string

To do this in one single line you can do something like:

Arrays.toString(str.split(".")).Contains("substring")

answered Sep 6, 2012 at 6:09

CloudyMarble

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Comments

npinti · Accepted Answer · 2012-09-06 06:12:32Z

Besides using the .contains method, which I think is best, you seem to want to build a data structure and search through it. To do something like that, you will need to do this:

String str = "This.is.a.great.place.too.work.";
String[] splitWords = str.split("\\.");  //The . is a special character in regex language, thus needs to be escaped. Alternatively you could use \\W which will split the string where ever it finds a character which is not a letter, digit or underscore.
List<String> words = Arrays.asList(splitWords);
System.out.println(words.contains("place"));

Alternatively, you could use the indexOf(String str) method like so:

if (str.indexOf("place") > 0)
{
    System.out.println("String Exists");
}

Deepak Swami · Accepted Answer · 2012-09-11 06:51:59Z

1

try this

string.split(pattern);
String[] strings = s.split(".")

Split will give array of strings which are splitted based on the paramater .

you cannot apply contains on string array , instead use the following

boolean flag = string.contains("required_pattern");

edited Sep 11, 2012 at 6:51

Deepak Swami

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answered Sep 6, 2012 at 6:05

abhi

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3 Comments

The Learner Over a year ago

can I not do Split and contains in the same line?>

abhi Over a year ago

no , split will give array of strings as output. contains() can be used only on string

CloudyMarble Over a year ago

You can do something like Arrays.toString(str.split(".")).Contains("substring") but it looks really ugly.

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