How to check if a string contains any element of a List<string>?

Question

I have an if statement, where I would like to check, if a string contains any item of a list<string>.

if (str.Contains(list2.Any()) && str.Contains(ddl_language.SelectedValue))
{
    lstpdfList.Items.Add(str);
}

Jon · Accepted Answer · 2017-03-20 17:15:07Z

56

The correct formulation is

list2.Any(s => str.Contains(s))

This is read as "does list2 include any string s such that str contains s?".

edited Mar 20, 2017 at 17:15

answered Sep 6, 2012 at 8:37

Jon

439k85 gold badges756 silver badges820 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

N K Over a year ago

And in case, if a dropdown list's selected value equal with an item from the list , how the formulation would be ?

Jon Over a year ago

@user1597284: If selectedValue is a string then list2.Contains(selectedValue). Take a look at the Enumerable class and all the extension methods it provides.

T-Dog Over a year ago

Is there any way to get the value of 's' after finding that 'str' contains 's'?

Jon Over a year ago

@T-Dog sure but you have to specify it better. Like what happens if there are multiple ss from the list contained inside str?

Jon Over a year ago

For example, if you replace Any with FirstOrDefault, the return value is going to be the first s that is contained in str or null if no such string exists in the list.

Dan Puzey · Accepted Answer · 2012-09-06 08:38:37Z

3

You could use this:

if (myList.Any(x => mystring.Contains(x)))
    // ....

answered Sep 6, 2012 at 8:38

Dan Puzey

34.3k4 gold badges77 silver badges98 bronze badges

1 Comment

N K Over a year ago

And in case, if a dropdown list's selected value equal with an item from the list , how the formulation would be ?

Collectives™ on Stack Overflow

How to check if a string contains any element of a List<string>?

2 Answers 2

5 Comments

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related