Adjust PHP code Retrieve the DOM from a given URL

Question

Hello ,

im using the following code to Retrieve the DOM from URL all "A" tags and print their HREFs Now my output is contain "A" i dont want its my out is here http://trend.remal.com/parsing.php

i need to clear my out to be only the name after http://twitter.com/namehere

so output print list of "namehere"

    include('simple_html_dom.php');

 // Retrieve the DOM from a given URL
 $html = file_get_html('http://tweepar.com/sa/1/');
 $urls = array();

  foreach ( $html->find('a') as $e )
  {
  // If it's a twitter link
  if ( strpos($e->href, '://twitter.com/') !== false )
  {
    // and we don't have it in the array yet
    if ( ! in_array($urls, $e->href) )
    {
        // add it to our array
        $urls[] = $e->href;
    }
   }
   }

  echo implode('<br>', $urls);

echo $e->href . '<br>';

The parameters to in_array are backward. If you want to search $urls for an instance of $e->href, use in_array($e->href, $urls). That will fix the "Warning: in_array() expects parameter 2 to be array, string given" problem. — Herbert
– Herbert, Commented Sep 9, 2012 at 10:57

Joseph Silber · Accepted Answer · 2012-09-09 10:58:37Z

2

Instead of simply using $urls[] = $e->href, use a regex to match the username:

preg_match('~twitter.com/(.+)~', $e->href, $matches);
$urls[] = $matches[1];

edited Sep 9, 2012 at 10:58

answered Sep 9, 2012 at 10:50

Joseph Silber

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