Perl regex String part to array

Question

I have a string:

"2012-szept-17 02:55 - someproblem: 192.167.1.1 since - $somevariables[0] $morevariables[-1]"

and I want to get these out of it into an array

$somevariables[0]
$morevariables[-1]

The problem is that these variables can be named anything else and they could be anywhere in the string. The only thing I know about them is that they start with $ and have [sg] in the end.

This is the furthest I got with the regexp

my @fuu = $notimsg =~ m/(\$.+\[.+\])/g;

The problem is that the expression is making this into "$somevariables[0] $morevariables[-1]"

nneonneo · Accepted Answer · 2012-09-17 02:21:51Z

1

If they must be valid variable names (identifiers), then try

m/(\$\w+\[[^]]+\])/g

As @Borodin points out, if you really want to make sure you match only identifiers (and not something strange like $3abc[12]), you can use

m/(\$[a-z_]\w*\[[^]]+\])/gi

edited Sep 17, 2012 at 2:21

answered Sep 17, 2012 at 1:25

nneonneo

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2 Comments

Borodin Over a year ago

This allows variable names starting with a digit. The correct regex is /(\$[a-z_]\w*\[[^]]+\])/i

nneonneo Over a year ago

I figure the array at the end makes it rather unlikely to crop up...after all, his problem is avoiding the spaces. Nevertheless, I'll edit to add.

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