preg_replace regex conflicting with others

Question

So i have this here

<? $regex = array('/@(\w+)/','/#(\w+)/','/((www|http:\/\/)[^ ]+)/');
    $replace = array(
    '<a href="https://www.twitter.com/$1">@$1</a>',
    '<a href="https://twitter.com/#!/search/%23$1">#$1</a>',
    '<a href="\1">\1</a>'
); ?>

<?= preg_replace($regex,$replace,stripslashes($row['tweet_text']));?>

The first two are suppose to turn anything with @ and # into links. This is obviously for twitter. But the third is supposed to turn anything with http or www into a link. But it seems to be conflicting with the first two messing up the links.

How can i make the third one make http or www links without conflicting the other two?

Tim Pietzcker · Accepted Answer · 2012-09-18 07:06:20Z

1

This is going to be hacky at best, but you could try this:

<? $regex = array('/((www|http:\/\/)[^ ]+)/', '/(?<!>)@(\w+)/', '/(?<!>)#(\w+)/');
    $replace = array(
    '<a href="\1">\1</a>',
    '<a href="https://www.twitter.com/$1">@$1</a>',
    '<a href="https://twitter.com/#!/search/%23$1">#$1</a>'
); ?>

Turn the order around, fixing the links first, then only replace @ and # handles if they are not preceded by a > (which they would be if they were already inside an anchor tag).

answered Sep 18, 2012 at 7:06

Tim Pietzcker

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1 Comment

Tim Pietzcker Over a year ago

@soniccool: Basically, yes. The (?<!>) is just an extra precaution.

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