COnverting Char Array to Long int

Question

How to convert Char array to long in obj c

 unsigned char *composite[4]; 
composite[0]=spIndex;
composite[1]= minor;
composite[2]=shortss[0];
composite[3]=shortss[1];

i need to convert this to Long int..Anyone please help

Please check these links maybe they will be of help :) stackoverflow.com/questions/169925/… stackoverflow.com/questions/3609972/… — IronManGill
– IronManGill, Commented Sep 24, 2012 at 6:38
So you want those 4 strings concatenated and then converted to an integer? Or did you perhaps mean unsigned char composite[4] instead? — trojanfoe
– trojanfoe, Commented Sep 24, 2012 at 6:42
i am trying to do something similar to this (new BigInteger(1,composite)) which is in java code — 012346
– 012346, Commented Sep 24, 2012 at 6:55
In java byte array composite value is [1, 9, 0, 10] and BigInteger comp = new BigInteger(1,composite); this gives 17367050 value i am not getting this value.my composite value is [0] 0x00000001,[1]0x0000005a,[2]0x00000000,[3]0x0000000a — 012346
– 012346, Commented Sep 24, 2012 at 7:11
And how do you hope to hold this value once you've converted it (given it's 128-bit)? You will need to implement your own version of BigInteger and this conversion is just one small part of that implementation. — trojanfoe
– trojanfoe, Commented Sep 24, 2012 at 7:59

aLevelOfIndirection · Accepted Answer · 2012-09-24 18:18:20Z

0

If you are looking at converting what is essentially already a binary number then a simple type cast would suffice but you would need to reverse the indexes to get the same result as you would in Java: long value = *((long*)composite);

You might also consider this if you have many such scenarios:

union {
  unsigned char asChars[4];
  long asLong;
} value;

value.asChar[3] = 1;
value.asChar[2] = 9;
value.asChar[1] = 0;
value.asChar[0] = 10;

// Outputs 17367050
NSLog(@"Value as long  %ld",value.asLong);

edited Sep 24, 2012 at 18:18

answered Sep 24, 2012 at 7:00

aLevelOfIndirection

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