How can I break an array into 2 arrays in c#
for e.g I have an array [1,2,3,4,5,6,7,8,9,10] break it in to [1,2,3,4,5] and [6,7,8,9,10]
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Refer this link, you may get some idea [Array][1] [1]: stackoverflow.com/questions/1367843/…Nagaraj– Nagaraj2012-10-01 05:33:47 +00:00Commented Oct 1, 2012 at 5:33
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possible duplicate of C# Splitting An Arraynawfal– nawfal2013-02-18 12:08:57 +00:00Commented Feb 18, 2013 at 12:08
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4 Answers
Using Linq
var a = new[] {1,2,3,4,5,6,7,8,9,10}
var a1 = a.Take(a.Length / 2).ToArray();
var a2 = a.Skip(a.Length / 2).ToArray();
Comments
With Linq:
var source = new int[] {1,2,3,4,5,6,7,8,9,10};
var firstHalf = source.Take(source.Length/2).ToArray();
var secondHalf = source.Skip(source.Length/2).ToArray();
With Array.Copy:
var source = new int[] {1,2,3,4,5,6,7,8,9,10};
var firstHalf = new int[source.Length/2];
var secondHalf = new int[source.Length - source.Length/2];
Array.Copy(source, firstHalf, firstHalf.Length];
Array.Copy(source, firstHalf.Length, secondHalf, 0, secondHalf.Length];
Comments
You could use the following method to split an array into 2 separate arrays
public void Split<T>(T[] array, int index, out T[] first, out T[] second) {
first = array.Take(index).ToArray();
second = array.Skip(index).ToArray();
}
public void SplitMidPoint<T>(T[] array, out T[] first, out T[] second) {
Split(array, array.Length / 2, out first, out second);
}
Usage:
int[] myArray = new int[] { 1,2,3,4,5,6,7,8,9,10 };
int[] newArray1;
int[] newArray2;
SplitMidPoint<int>(myArray, out newArray1, out newArray2);
From: C# Splitting An Array
Comments
public static T[] SubArray(this T[] data, int index, int length)
{
T[] result = new T[length];
Array.Copy(data, index, result, 0, length);
return result;
}
public void Split(T[] Source, T[] arr1,T[] arr2)
{
if(source.Length == 0)
{
arr1 = arr2 = new T[0];
return ;
}
int half = source.Length/2;
arr1 = source.SubArray(0, half);
arr2 = source.SubArray(half-1, half);
}
