Accessing data from CakePHP's find() return array

Question

Here's an example of an array that is returned by CakePHP's find() method:

Array 
(
    [Tutor] => Array 
    ( 
        [id] => 2 
        [PersonaId] => 1 
    ) 
)

The official documentation shows how to fetch records, but does not show how to iterate through them or even read out a single value. I'm kind of lost at this point. I'm trying to fetch the [id] value within the array. Here's what I've tried:

// $tutor is the array.
print_r($tutor[0]->id);

Notice (8): Undefined offset: 0 [APP\Controller\PersonasController.php, line 43]

Notice (8): Trying to get property of non-object [APP\Controller\PersonasController.php, line 43]

I've also tried:

// $tutor is the array.
print_r($tutor->id);

Notice (8): Trying to get property of non-object [APP\Controller\PersonasController.php, line 44]

MDEV · Accepted Answer · 2012-10-03 21:23:14Z

1

The -> way of accessing properties is used in objects. What you have shown us is an array. In that example, accessing the id would require

$tutor['Tutor']['id']

Official PHP documentation, "Accessing array elements with square bracket syntax":

<?php
$array = array(
    "foo" => "bar",
    42    => 24,
    "multi" => array(
         "dimensional" => array(
             "array" => "foo"
         )
    )
);

var_dump($array["foo"]); //"bar"
var_dump($array[42]); //24
var_dump($array["multi"]["dimensional"]["array"]); //"foo"
?>

edited Oct 3, 2012 at 21:23

answered Oct 3, 2012 at 21:19

MDEV

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1 Comment

sergserg Over a year ago

Thanks this helped. I went ahead and added some official PHP documentation and examples to further explain how it works.

user399666 · Accepted Answer · 2012-10-03 21:18:11Z

0

The returned value is an array, not an object. This should work:

echo $tutor['Tutor']['id'];

Or:

foreach($tutor as $tut){
    echo $tut['Tutor']['id'] . '<br />';
}

answered Oct 3, 2012 at 21:18

user399666

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