Oracle REGEXP_REPLACE uppercase replacement string

Question

I am attempting to uppercase the replacement string from my reg expression without success:

SELECT regexp_replace('src=/i/uie_v2/js','(/uie_v2/)',upper('\1')) from dual

returns 'src=/i/uie_v2/js'

I understand that upper cannot be used .. just showing as an example. Any ideas on how to achieve this ?

Frank Schmitt · Accepted Answer · 2012-10-04 12:10:53Z

4

AFAIK, you cannot do this directly, but you can take the string apart and rebuild it:

SELECT regexp_replace('src=/i/uie_v2/js','(.*)(/uie_v2/)(.*)', '\1') ||
  upper(regexp_substr('src=/i/uie_v2/js','(/uie_v2/)')) || 
  regexp_replace('src=/i/uie_v2/js','(.*)(/uie_v2/)(.*)', '\3')
from dual

I got the idea from an OTN forums thread on REGEXP.

answered Oct 4, 2012 at 12:10

Frank Schmitt

30.5k13 gold badges79 silver badges111 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Oracle REGEXP_REPLACE uppercase replacement string

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related