I am using the following:
return string.Join("\n", parts);
Parts has 7 entries but two of them are the empty string "". How can I first remove these two entries and then join the remaining five?
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4 Answers
You can use Where in LINQ to select strings which are not empty:
return string.Join("\n", parts.Where(s => !string.IsNullOrEmpty(s)));
Comments
An alternate way of doing this is by using StringSplitOptions.RemoveEmptyEntries:
e.g.
string yourString = "The|quick||brown|||fox|is|here";
char[] delimiter = new char[] { '|' };
string result = string.Join(",", yourString.Split(delimiter, StringSplitOptions.RemoveEmptyEntries));
This gives:
The,quick,brown,fox,is,here
@Stefan Steiger:
string yourString = "echo 'foo' | sed '/foo/d;'";
This gives:
echo 'foo' , sed '/foo/d;'
Which is as I would expect. See the dotnetfiddle of it.
2 Comments
Michael come lately
Is
Values a string like "foo|bar||baz|||baf"?
Stefan Steiger
And now I enter a value like "echo 'foo' | sed '/foo/d;'" and it breaks horribly.
Try it using LINQ
string[] hello = new string[] { "ads", "zxc", "wer", "", "wer", "", "243" };
string newString = string.Join("\n", hello.Where(x => x.Trim().Length != 0));
MessageBox.Show(newString);
or
return string.Join("\n", hello.Where(x => x.Trim().Length != 0));
Comments
To do it in .NET 2.0 (no LINQ), e.g. for ReportingServices without writing a function for it:
C#
string a = "", b = "b", c = "", d = "d", e = "";
string lala = string.Join(" / ",
string.Join("\u0008", new string[] { a, b, c, d, e }).Split(new char[] { '\u0008' }, System.StringSplitOptions.RemoveEmptyEntries)
);
System.Console.WriteLine(lala);
VB.NET
Dim a As String = "", b As String = "b", c As String = "", d As String = "d", e As String = ""
Dim lala As String = String.Join(" / ", String.Join(vbBack, New String() {a, b, c, d, e}).Split(New Char() {ControlChars.Back}, System.StringSplitOptions.RemoveEmptyEntries))
System.Console.WriteLine(lala)
This assumes that the character backspace doesn't occur in your strings (should usually be true, because you can't simply enter this character by keyboard).