Replace LinkedList element value through LinkedList.Enumerator

Question

I realize there are no way for me to replace value through LinkedList.Enumerator.

For instance, I try to port the below Java code to C#:

Java code:

ListIterator<Double> itr1 = linkedList1.listIterator();
ListIterator<Double> itr2 = linkedList2.listIterator();
while(itr1.hasNext() && itr2.hasNext()){
    Double d = itr1.next() + itr2.next();
    itr1.set(d);
}

C# code:

LinkedList<Double>.Enumerator itr1 = linkedList1.GetEnumerator();            
LinkedList<Double>.Enumerator itr2 = linkedList2.GetEnumerator();

 while(itr1.MoveNext() && itr2.MoveNext()){                
    Double d = itr1.Current + itr2.Current;
    // Opps. Compilation error!
    itr1.Current = d;
}

Any other techniques I can use?

Paolo Moretti · Accepted Answer · 2012-10-08 09:59:59Z

5

C#'s LinkedList enumerator enumerates the values, not the nodes.

If you want to modify nodes as in the Java version, I think you have to "enumerate" the nodes manually:

LinkedListNode<Double> nod1 = linkedList1.First;
LinkedListNode<Double> nod2 = linkedList2.First;
while (nod1 != null && nod2 != null)
{
    Double d = nod1.Value + nod2.Value;              
    nod1.Value = d;
    nod1 = nod1.Next;
    nod2 = nod2.Next;
}

edited Oct 8, 2012 at 9:59

Paolo Moretti

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answered Oct 8, 2012 at 9:46

Rawling

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Comments

JohnB · Accepted Answer · 2012-10-08 16:20:36Z

0

Maybe it's sufficient to simply build a new list:

linkedList1 = new LinkedList<double> (linkedList1.Zip(linkedList2, (first, second) => first + second));

If you need the original list to be changed, you might want to do

 var tmp = linkedList1.Zip(linkedList2, (first, second) => first + second).ToList ();
 linkedList1.Clear ();
 linkedList1.AddRange (tmp);

edited Oct 8, 2012 at 16:20

answered Oct 8, 2012 at 9:41

JohnB

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3 Comments

Paolo Moretti Over a year ago

linkedList1 is a LinkedList<double> so you can't use .ToList(); You need something like: linkedList1 = new LinkedList<double>(linkedList1.Zip(linkedList2, (first, second) => first + second));

JohnB Over a year ago

Why shouldn't I be able to use ToList () for a List<double>???? I just tried it, and I do not see any problem. It does what it is supposed to do.

Paolo Moretti Over a year ago

Because it's not a List<>, it's a LinkedList<>

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