Stuck with while loop. In processing

Question

I have an array of 100 numbers and I only gave the array even values. How can I print out how many elements of the array I have to add to obtain a sum < than 1768 using a WHILE LOOP? The following is what I have so far and I am stuck... thanks in advance for the help

void setup() {

  int[] x = new int[100];
  int i=0;
  int sum=0;

  for(i=0; i<100; i++) {
    if (i%2==0) {
      x[i]=i;
      sum+=x[i];
    }
  }
}

how many elements -> You need to say more.. Minimum no or maximum no? Or it doesn't matter? — Rohit Jain
– Rohit Jain, Commented Oct 15, 2012 at 14:51
sorry! i need the max number of elements before the sum of even numbers which is what i assigned to the array is 1768! — choloboy
– choloboy, Commented Oct 15, 2012 at 14:53
If one of your requirements say to use a while loop, why does your current progress utilize a for loop? — Dan W
– Dan W, Commented Oct 15, 2012 at 15:03

Alexey Ivanov · Accepted Answer · 2012-10-15 16:06:28Z

2

 void setup() {
     int i = 0;
     int sum = 0;
     int counter = 0;

     while (sum < 1768) {
         sum += i;
         i += 2;
         counter++;
     }

     System.out.println(counter);
 }

You start with the even index of 0. Then just skip odd numbers by using i += 2.
If the number of elements is limited with 100, add i < 200 to the while condition:

while (sum < 1768 && i < 200)

_{The array of 100 even numbers will contain numbers from 0 to 200.}

The variable counter will contain the number of additions performed. Its value will be equal to i / 2, so you can remove that additional variable.

edited Oct 15, 2012 at 16:06

answered Oct 15, 2012 at 15:06

Alexey Ivanov

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Comments

Subhrajyoti Majumder · Accepted Answer · 2012-10-15 14:56:41Z

2

You can use this loop and element number would be i+1.

       for(int i=0,k=0; k<1768; i++,k+=x[i]) {
        System.out.println(x[i]+" - "+k);
       }

While loop -

   int i=0,k=0;
   while(k<1768; ) {
        System.out.println(x[i]+" - "+k);
        i++,k+=x[i];
       }

answered Oct 15, 2012 at 14:56

Subhrajyoti Majumder

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3 Comments

choloboy Over a year ago

Any way to see this in a while loop?

Duncan Jones Over a year ago

@Quoi Based on the strange requirement and the odd restriction, it's probably homework.

choloboy Over a year ago

it is a tutorial... Self improvement.

getit · Accepted Answer · 2012-10-15 15:08:21Z

2

You are skipping indexes in your array.You are only filling every other 'slot' Also, it would probably be easier to use a while loop to check against your max value (1728)

        int[] x = new int[100];
        int i = 0;
        int sum = 0;
        int max = 1728;

        while (sum < max && i < 100)
        {
            x[i] = i*2;
            if ((x[i] + sum) < max)
            {
                sum += x[i];
            }
            i++;
        }

answered Oct 15, 2012 at 15:08

getit

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Comments

user1572130 · Accepted Answer · 2012-10-15 15:10:22Z

1

void setup() {

  int[] x = new int[100];
  int maxValue = 1768;
  int i;
  int sum=0;

  while(sum<maxValue) {
    if (i%2==0) {
      x[i]=i;
      sum+=x[i];
      i++;
    }
  }

   System.out.println(i+" Elements needed")

}

edited Oct 15, 2012 at 15:10

answered Oct 15, 2012 at 15:01

user1572130

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Comments

w3b · Accepted Answer · 2012-10-15 14:56:16Z

-1

following is code:

void setup() {

  int[] x = new int[100];
  int i=0;
  int sum=0;

  for(i=0; i<100; i++) {
    if (i%2==0) {
      sum += i;
            if(sum<1768){

                 num +=1; 
            }
    }
  }
}

answered Oct 15, 2012 at 14:56

w3b

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4 Comments

Duncan Jones Over a year ago

We need a Java answer for this question.

choloboy Over a year ago

that is similar to what I initially had, but it must be completed using a while loop!

Duncan Jones Over a year ago

"Must be completed using a while loop" > that's news to us. Is that a requirement?

choloboy Over a year ago

yes it is, sorry i forgot to mention that in the question! sorry!

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